What is Methods Overloading
Overloaded methods have the same name but different parameters.
Overloaded methods must differ in the type and/or number of their parameters.
Overloaded methods may have different
return types.return type alone is insufficient to distinguish two methods.The following example illustrates method overloading:
class OverloadDemo {
void test() {
System.out.println("No parameters");
}
void test(int a) {
System.out.println("a: " + a);
}
void test(int a, int b) {
System.out.println("a and b: " + a + " " + b);
}
double test(double a) {
System.out.println("double a: " + a);
return a * a;
}
}
public class Main {
public static void main(String args[]) {
OverloadDemo ob = new OverloadDemo();
ob.test();
ob.test(10);
ob.test(10, 20);
double result = ob.test(123.25);
System.out.println("Result of ob.test(123.25): " + result);
}
}
This program generates the following output:
No parameters
a: 10
a and b: 10 20
double a: 123.25
Result of ob.test(123.25): 15190.5625
Automatic type conversions apply to overloading
class OverloadDemo {
void test() {
System.out.println("No parameters");
}
void test(int a, int b) {
System.out.println("a and b: " + a + " " + b);
}
void test(double a) {
System.out.println("Inside test(double) a: " + a);
}
}
public class Main {
public static void main(String args[]) {
OverloadDemo ob = new OverloadDemo();
int i = 88;
ob.test();
ob.test(10, 20);
ob.test(i); // this will invoke test(double)
ob.test(123.2); // this will invoke test(double)
}
}
This program generates the following output:
No parameters
a and b: 10 20
Inside test(double) a: 88.0
Inside test(double) a: 123.2