Format integer with eight hexadecimal digits : int format « Data Types « C# / C Sharp

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C# / C Sharp » Data Types » int format

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Format integer with eight hexadecimal digits

   



using System;

using System.Globalization;



public class Example

{

   public static void Main()

   {

      int[] numbers = { -111, 0, 169, 11111 };

      foreach (int number in numbers) {

         // Display value with eight hexadecimal digits.

         Console.WriteLine("{0,14:X8}", number);

      }

   }

}

/*



      FFFFFF91

      00000000

      000000A9

      00002B67





*/

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