Format integer with eight hexadecimal digits : int format « Data Types « C# / C Sharp

1. C# / C Sharp
2. Data Types
3. int format

Format integer with eight hexadecimal digits

   

using System;
using System.Globalization;

public class Example
{
   public static void Main()
   {
      int[] numbers = { -111, 0, 169, 11111 };
      foreach (int number in numbers) {
         // Display value with eight hexadecimal digits.
         Console.WriteLine("{0,14:X8}", number);
      }
   }
}
/*

      FFFFFF91
      00000000
      000000A9
      00002B67


*/

   
    
    
  

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