Compare two String[] for differences, either may be null : String Compare « Data Type « Java






  1. Java
  2. Data Type
  3. String Compare

Compare two String[] for differences, either may be null

     
import java.util.Collection;
import java.util.Iterator;

/**********************************************************************************
 * $URL: https://source.sakaiproject.org/svn/util/branches/sakai_2-5-4/util-util/util/src/java/org/sakaiproject/util/StringUtil.java $
 * $Id: StringUtil.java 34934 2007-09-10 22:52:23Z lance@indiana.edu $
 ***********************************************************************************
 *
 * Copyright (c) 2003, 2004, 2005, 2006 The Sakai Foundation.
 * 
 * Licensed under the Educational Community License, Version 1.0 (the "License"); 
 * you may not use this file except in compliance with the License. 
 * You may obtain a copy of the License at
 * 
 *      http://www.opensource.org/licenses/ecl1.php
 * 
 * Unless required by applicable law or agreed to in writing, software 
 * distributed under the License is distributed on an "AS IS" BASIS, 
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. 
 * See the License for the specific language governing permissions and 
 * limitations under the License.
 *
 **********************************************************************************/



/**
 * <p>
 * StringUtil collects together some string utility classes.
 * </p>
 */
public class StringUtil
{


  /**
   * Compare two String[] for differences, either may be null
   * 
   * @param a
   *        One String[].
   * @param b
   *        The other String[].
   * @return true if the String[]s are different, false if they are the same.
   */
  public static boolean different(String[] a, String[] b)
  {
    // if both null, they are the same
    if ((a == null) && (b == null)) return false;

    // if either are null (they both are not), they are different
    if ((a == null) || (b == null)) return true;

    // if the lengths are different, they are different
    if (a.length != b.length) return true;

    // now we know neither are null, so compare, item for item (order counts)
    for (int i = 0; i < a.length; i++)
    {
      if (!a[i].equals(b[i])) return true;
    }

    // they are NOT different!
    return false;
  }

}








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