# Normalize an angle in a 2&pi wide interval around a center value. : Math « Development Class « Java

Normalize an angle in a 2&pi wide interval around a center value.

```
import java.io.File;

/*
* Licensed to the Apache Software Foundation (ASF) under one or more
*  contributor license agreements.  See the NOTICE file distributed with
*  this work for additional information regarding copyright ownership.
*  The ASF licenses this file to You under the Apache License, Version 2.0
*  (the "License"); you may not use this file except in compliance with
*  the License.  You may obtain a copy of the License at
*
*
*  Unless required by applicable law or agreed to in writing, software
*  distributed under the License is distributed on an "AS IS" BASIS,
*  WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
*  See the License for the specific language governing permissions and
*  limitations under the License.
*
*
*/
public class Main {
/** 2 &pi;. */
private static final double TWO_PI = 2 * Math.PI;
/**
* Normalize an angle in a 2&pi wide interval around a center value.
* <p>This method has three main uses:</p>
* <ul>
*   <li>normalize an angle between 0 and 2&pi;:<br/>
*       <code>a = MathUtils.normalizeAngle(a, Math.PI);</code></li>
*   <li>normalize an angle between -&pi; and +&pi;<br/>
*       <code>a = MathUtils.normalizeAngle(a, 0.0);</code></li>
*   <li>compute the angle between two defining angular positions:<br>
*       <code>angle = MathUtils.normalizeAngle(end, start) - start;</code></li>
* </ul>
* <p>Note that due to numerical accuracy and since &pi; cannot be represented
* exactly, the result interval is <em>closed</em>, it cannot be half-closed
* as would be more satisfactory in a purely mathematical view.</p>
* @param a angle to normalize
* @param center center of the desired 2&pi; interval for the result
* @return a-2k&pi; with integer k and center-&pi; &lt;= a-2k&pi; &lt;= center+&pi;
* @since 1.2
*/
public static double normalizeAngle(double a, double center) {
return a - TWO_PI * Math.floor((a + Math.PI - center) / TWO_PI);
}

}

```

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