GROUPING() returns 0 for the rows that have non-null values, and 1 for the last row that has a null value
SQL>
SQL> -- create demo table
SQL> create table Employee(
2 ID VARCHAR2(4 BYTE) NOT NULL,
3 First_Name VARCHAR2(10 BYTE),
4 Last_Name VARCHAR2(10 BYTE),
5 Start_Date DATE,
6 End_Date DATE,
7 Salary Number(8,2),
8 City VARCHAR2(10 BYTE),
9 Description VARCHAR2(15 BYTE)
10 )
11 /
Table created.
SQL>
SQL> -- prepare data
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values ('01','Jason', 'Martin', to_date('19960725','YYYYMMDD'), to_date('20060725','YYYYMMDD'), 1234.56, 'Toronto', 'Programmer')
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values('02','Alison', 'Mathews', to_date('19760321','YYYYMMDD'), to_date('19860221','YYYYMMDD'), 6661.78, 'Vancouver','Tester')
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values('03','James', 'Smith', to_date('19781212','YYYYMMDD'), to_date('19900315','YYYYMMDD'), 6544.78, 'Vancouver','Tester')
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values('04','Celia', 'Rice', to_date('19821024','YYYYMMDD'), to_date('19990421','YYYYMMDD'), 2344.78, 'Vancouver','Manager')
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values('05','Robert', 'Black', to_date('19840115','YYYYMMDD'), to_date('19980808','YYYYMMDD'), 2334.78, 'Vancouver','Tester')
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values('06','Linda', 'Green', to_date('19870730','YYYYMMDD'), to_date('19960104','YYYYMMDD'), 4322.78,'New York', 'Tester')
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values('07','David', 'Larry', to_date('19901231','YYYYMMDD'), to_date('19980212','YYYYMMDD'), 7897.78,'New York', 'Manager')
3 /
1 row created.
SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)
2 values('08','James', 'Cat', to_date('19960917','YYYYMMDD'), to_date('20020415','YYYYMMDD'), 1232.78,'Vancouver', 'Tester')
3 /
1 row created.
SQL>
SQL>
SQL>
SQL> -- display data in the table
SQL> select * from Employee
2 /
ID FIRST_NAME LAST_NAME START_DATE END_DATE SALARY CITY DESCRIPTION
---- ---------- ---------- ----------- ----------- ---------- ---------- ---------------
01 Jason Martin 1996-JUL-25 2006-JUL-25 1234.56 Toronto Programmer
02 Alison Mathews 1976-MAR-21 1986-FEB-21 6661.78 Vancouver Tester
03 James Smith 1978-DEC-12 1990-MAR-15 6544.78 Vancouver Tester
04 Celia Rice 1982-OCT-24 1999-APR-21 2344.78 Vancouver Manager
05 Robert Black 1984-JAN-15 1998-AUG-08 2334.78 Vancouver Tester
06 Linda Green 1987-JUL-30 1996-JAN-04 4322.78 New York Tester
07 David Larry 1990-DEC-31 1998-FEB-12 7897.78 New York Manager
08 James Cat 1996-SEP-17 2002-APR-15 1232.78 Vancouver Tester
8 rows selected.
SQL>
SQL>
SQL> --GROUPING() returns 0 for the rows that have non-null values, and 1 for the last row that has a null value:
SQL>
SQL> SELECT GROUPING(city), city, SUM(salary)
2 FROM employee
3 GROUP BY ROLLUP(city);
GROUPING(CITY) CITY SUM(SALARY)
-------------- ---------- -----------
0 New York 12220.56
0 Toronto 1234.56
0 Vancouver 19118.9
1 32574.02
SQL>
SQL>
SQL>
SQL> -- clean the table
SQL> drop table Employee
2 /
Table dropped.
SQL>
SQL>
SQL>
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