ROW_NUMBER function with an ordering on salary in descending order

 


SQL>
SQL> -- create demo table
SQL> create table Employee(
  2    ID                 VARCHAR2(4 BYTE)         NOT NULL,
  3    First_Name         VARCHAR2(10 BYTE),
  4    Last_Name          VARCHAR2(10 BYTE),
  5    Start_Date         DATE,
  6    End_Date           DATE,
  7    Salary             Number(8,2),
  8    City               VARCHAR2(10 BYTE),
  9    Description        VARCHAR2(15 BYTE)
 10  )
 11  /

Table created.

SQL>
SQL> -- prepare data
SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)
  2               values ('01','Jason',    'Martin',  to_date('19960725','YYYYMMDD'), to_date('20060725','YYYYMMDD'), 1234.56, 'Toronto',  'Programmer')
  3  /

1 row created.

SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)
  2                values('02','Alison',   'Mathews', to_date('19760321','YYYYMMDD'), to_date('19860221','YYYYMMDD'), 2334.78, 'Vancouver','Tester')
  3  /

1 row created.

SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)
  2                values('03','James',    'Smith',   to_date('19781212','YYYYMMDD'), to_date('19900315','YYYYMMDD'), 2334.78, 'Vancouver','Tester')
  3  /

1 row created.

SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)
  2                values('04','Celia',    'Rice',    to_date('19821024','YYYYMMDD'), to_date('19990421','YYYYMMDD'), 2334.78, 'Vancouver','Manager')
  3  /

1 row created.

SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)
  2                values('05','Robert',   'Black',   to_date('19840115','YYYYMMDD'), to_date('19980808','YYYYMMDD'), 2334.78, 'Vancouver','Tester')
  3  /

1 row created.

SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary, City,        Description)
  2                values('06','Linda',    'Green',   to_date('19870730','YYYYMMDD'), to_date('19960104','YYYYMMDD'), 2334.78,'New York',  'Tester')
  3  /

1 row created.

SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary, City,        Description)
  2                values('07','David',    'Larry',   to_date('19901231','YYYYMMDD'), to_date('19980212','YYYYMMDD'), 2334.78,'New York',  'Manager')
  3  /

1 row created.

SQL> insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary, City,        Description)
  2                values('08','James',    'Cat',     to_date('19960917','YYYYMMDD'), to_date('20020415','YYYYMMDD'), 2334.78,'Vancouver', 'Tester')
  3  /

1 row created.

SQL>
SQL>
SQL>
SQL> -- display data in the table
SQL> select * from Employee
  2  /

ID   FIRST_NAME LAST_NAME  START_DAT END_DATE      SALARY CITY       DESCRIPTION
---- ---------- ---------- --------- --------- ---------- ---------- ---------------
01   Jason      Martin     25-JUL-96 25-JUL-06    1234.56 Toronto    Programmer
02   Alison     Mathews    21-MAR-76 21-FEB-86    2334.78 Vancouver  Tester
03   James      Smith      12-DEC-78 15-MAR-90    2334.78 Vancouver  Tester
04   Celia      Rice       24-OCT-82 21-APR-99    2334.78 Vancouver  Manager
05   Robert     Black      15-JAN-84 08-AUG-98    2334.78 Vancouver  Tester
06   Linda      Green      30-JUL-87 04-JAN-96    2334.78 New York   Tester
07   David      Larry      31-DEC-90 12-FEB-98    2334.78 New York   Manager
08   James      Cat        17-SEP-96 15-APR-02    2334.78 Vancouver  Tester

8 rows selected.

SQL>
SQL>
SQL>
SQL>
SQL> -- ROW_NUMBER function with an ordering on salary in descending order:
SQL>
SQL> SELECT id, first_name, salary, ROW_NUMBER() OVER(ORDER BY salary desc) toprank FROM employee;

ID   FIRST_NAME     SALARY    TOPRANK
---- ---------- ---------- ----------
04   Celia         2334.78          1
02   Alison        2334.78          2
03   James         2334.78          3
08   James         2334.78          4
05   Robert        2334.78          5
06   Linda         2334.78          6
07   David         2334.78          7
01   Jason         1234.56          8

8 rows selected.

SQL>
SQL>
SQL>
SQL>
SQL>
SQL> -- clean the table
SQL> drop table Employee;

Table dropped.

SQL>
SQL>

Related examples in the same category

1.	ROW_NUMBER(): return a number with each row in a group, starting at 1
2.	More Than One Analytical Function May Be Used in a Single Statement ROW_NUMBER(), RANK(), DENSE_RANK()
3.	ROW_NUMBER() with order in descending order
4.	Rank() with nulls last
5.	row_number over partition by and order by
6.	Sum over and row_number() over
7.	Decode the result from row_number over, partition by, order by
8.	Open a cursor created by using row_number function
9.	Create a view based on row_number function
10.	row_number() over (partition by deptno order)

ROW_NUMBER function with an ordering on salary in descending order : ROW_NUMBER « Analytical Functions « Oracle PL / SQL

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