Get the log of 8, base 2 : LOG « Numeric Math Functions « Oracle PL / SQL






Get the log of 8, base 2



SQL> -- create demo table
SQL> create table TestTable(
  2    ID                 VARCHAR2(4 BYTE)         NOT NULL,
  3    MyName             VARCHAR2(10 BYTE),
  4    MyDate             DATE,
  5    MyNumber           Number(8,2)
  6  )
  7  /

Table created.

SQL>
SQL>
SQL> insert into TestTable (ID, MyName, MyDate, MyNumber) values('1','Alison',to_date('19960711','YYYYMMDD'),12.12);

1 row created.

SQL> insert into TestTable (ID, MyName, MyDate, MyNumber) values('1','Alison',to_date('19970622','YYYYMMDD'),1.12);

1 row created.

SQL> insert into TestTable (ID, MyName, MyDate, MyNumber) values('1','Alison',to_date('19980513','YYYYMMDD'),22.1);

1 row created.

SQL> insert into TestTable (ID, MyName, MyDate, MyNumber) values('1','Alison',to_date('19990624','YYYYMMDD'),2.12);

1 row created.

SQL> insert into TestTable (ID, MyName, MyDate, MyNumber) values('1','Alison',to_date('20000415','YYYYMMDD'),2.1);

1 row created.

SQL>
SQL>
SQL> select * from TestTable
  2
SQL>
SQL> --Get the log of 8, base 2
SQL> SELECT LOG(2,8), LOG(2,MyNumber) FROM TestTable;

  LOG(2,8) LOG(2,MYNUMBER)
---------- ---------------
         3      3.59931779
         3      .163498732
         3      4.46597446
         3      1.08406426
         3      1.07038933

SQL>
SQL>
SQL>
SQL>
SQL>
SQL>
SQL> drop table TestTable;

Table dropped.

SQL>
           
       








Related examples in the same category

1.LOG: The first argument is the base, and the second is the number that you want to take the log of
2.LOG(x, y):Returns the logarithm, base x, of y
3.LOG(2, 5)