A match for any vowel followed by an 'r' or 'p' : Brackets « Regular Expressions « Oracle PL / SQL






A match for any vowel followed by an 'r' or 'p'



SQL> create table TestTable(
  2    ID                    VARCHAR2(4 BYTE)         NOT NULL,
  3    Description           VARCHAR2(40 BYTE)
  4  )
  5  /

Table created.

SQL>
SQL>
SQL> insert into TestTable (ID, Description) values('1','1234 5th Street');

1 row created.

SQL> insert into TestTable (ID, Description) values('2','1 Culloden Street');

1 row created.

SQL> insert into TestTable (ID, Description) values('3','1234 Road');

1 row created.

SQL> insert into TestTable (ID, Description) values('4','33 Thrid Road');

1 row created.

SQL> insert into TestTable (ID, Description) values('5','One than another');

1 row created.

SQL> insert into TestTable (ID, Description) values('6','2003 Movie');

1 row created.

SQL> insert into TestTable (ID, Description) values('7','Start With Letters');

1 row created.

SQL>
SQL> select * from TestTable;

ID   DESCRIPTION
---- ----------------------------------------
1    1234 5th Street
2    1 Culloden Street
3    1234 Road
4    33 Thrid Road
5    One than another
6    2003 Movie
7    Start With Letters

7 rows selected.

SQL>
SQL>
SQL>
SQL>
SQL> -- A match for any vowel followed by an 'r' or 'p'
SQL>
SQL> SELECT description, REGEXP_INSTR(description,'[aeiou][rp]') where_it_is
  2  FROM testTable
  3  WHERE REGEXP_INSTR(description,'[aeiou][rp]') > 0;

DESCRIPTION                              WHERE_IT_IS
---------------------------------------- -----------
One than another                                  15
Start With Letters                                 3

SQL>
SQL> drop table TestTable;

Table dropped.

SQL>
SQL>
SQL>
           
       








Related examples in the same category

1.[whatever]: a match of whatever set of characters is included inside the brackets in any order
2.Select only addresses that contain vowels
3.REGEXP_INSTR(description,'[aeiou][aeiou]'): Look for two consecutive vowels