Parenthesize both expressions : Group « Regular Expressions « Oracle PL / SQL






Parenthesize both expressions



SQL> create table TestTable(
  2    ID                    VARCHAR2(4 BYTE)         NOT NULL,
  3    Description           VARCHAR2(30 BYTE)
  4  )
  5  /

Table created.

SQL>
SQL>
SQL> insert into TestTable (ID, Description) values('1','1234 5th Street');

1 row created.

SQL> insert into TestTable (ID, Description) values('2','1 Culloden Street');

1 row created.

SQL> insert into TestTable (ID, Description) values('3','1234 Road');

1 row created.

SQL> insert into TestTable (ID, Description) values('4','33 Thrid Road');

1 row created.

SQL> insert into TestTable (ID, Description) values('5','One than another');

1 row created.

SQL> insert into TestTable (ID, Description) values('6','2003 Movie');

1 row created.

SQL> insert into TestTable (ID, Description) values('7','Start With Letters');

1 row created.

SQL>
SQL> select * from TestTable;

ID   DESCRIPTION
---- ------------------------------
1    1234 5th Street
2    1 Culloden Street
3    1234 Road
4    33 Thrid Road
5    One than another
6    2003 Movie
7    Start With Letters

7 rows selected.

SQL>
SQL>
SQL>
SQL> -- Parenthesize both expressions
SQL>
SQL> SELECT description, REGEXP_SUBSTR(description,'(ir)d|s') FROM testTable;

DESCRIPTION                    REGEXP_SUBSTR(DESCRIPTION,'(IR
------------------------------ ------------------------------
1234 5th Street
1 Culloden Street
1234 Road
33 Thrid Road
One than another
2003 Movie
Start With Letters             s

7 rows selected.

SQL>
SQL>
SQL> drop table TestTable;

Table dropped.

SQL>
SQL>
SQL>
           
       








Related examples in the same category

1.Group the letters 'ir' together by putting them in parentheses
2.REGEXP_SUBSTR('Yababa dababa do','(ab)')
3.Using backreference: REGEXP_REPLACE('H1234 H4321 H2345','(.*) (.*) (.*)','\3, \2 \1')
4.REGEXP_SUBSTR('Yababa dababa do','(ab)\1'), backreference option