next() raises a StopIteration exception tellint the for loop to terminate : next « Buildin Function « Python

1. Python
2. Buildin Function
3. next

next() raises a StopIteration exception tellint the for loop to terminate

s = 'abcdef'
it = iter(s)
it

print it.next()

print it.next()

print it.next()

print it.next()


           
       

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