Sorting in User-Defined Orders : Sort Order « Select Clause « SQL / MySQL






Sorting in User-Defined Orders

       
mysql>
mysql> CREATE TABLE driver_log
    -> (
    ->  rec_id          INT UNSIGNED NOT NULL AUTO_INCREMENT,
    ->  name            VARCHAR(20) NOT NULL,
    ->  trav_date       DATE NOT NULL,
    ->  miles           INT NOT NULL,
    ->  PRIMARY KEY (rec_id)
    -> );
Query OK, 0 rows affected (0.00 sec)

mysql>
mysql> INSERT INTO driver_log (name,trav_date,miles)
    ->  VALUES
    ->          ('Ben','2010-11-30',152),
    ->          ('Suzi','2010-11-29',391),
    ->          ('Henry','2010-11-29',300),
    ->          ('Henry','2010-11-27',96),
    ->          ('Ben','2010-11-29',131),
    ->          ('Henry','2010-11-26',115),
    ->          ('Suzi','2010-12-02',502),
    ->          ('Henry','2010-12-01',197),
    ->          ('Ben','2010-12-02',79),
    ->          ('Henry','2010-11-30',203)
    -> ;
Query OK, 10 rows affected (0.00 sec)
Records: 10  Duplicates: 0  Warnings: 0

mysql> SELECT * FROM driver_log
    -> ORDER BY FIELD(name,'Henry','Suzi','Ben');
+--------+-------+------------+-------+
| rec_id | name  | trav_date  | miles |
+--------+-------+------------+-------+
|     10 | Henry | 2010-11-30 |   203 |
|      8 | Henry | 2010-12-01 |   197 |
|      6 | Henry | 2010-11-26 |   115 |
|      4 | Henry | 2010-11-27 |    96 |
|      3 | Henry | 2010-11-29 |   300 |
|      7 | Suzi  | 2010-12-02 |   502 |
|      2 | Suzi  | 2010-11-29 |   391 |
|      5 | Ben   | 2010-11-29 |   131 |
|      9 | Ben   | 2010-12-02 |    79 |
|      1 | Ben   | 2010-11-30 |   152 |
+--------+-------+------------+-------+
10 rows in set (0.00 sec)

mysql>
mysql> drop table driver_log;
Query OK, 0 rows affected (0.00 sec)

   
    
    
    
    
    
    
  








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