Subqueries and ANY operator : Subqueries ANY « Subquery « SQL Server / T-SQL






Subqueries and ANY operator


29>
30> CREATE TABLE employee  (emp_no    INTEGER NOT NULL,
31>                         emp_fname CHAR(20) NOT NULL,
32>                         emp_lname CHAR(20) NOT NULL,
33>                         dept_no   CHAR(4) NULL)
34>
35> insert into employee values(1,  'Matthew', 'Smith',    'd3')
36> insert into employee values(2,  'Ann',     'Jones',    'd3')
37> insert into employee values(3,  'John',    'Barrimore','d1')
38> insert into employee values(4,  'James',   'James',    'd2')
39> insert into employee values(5,  'Elsa',    'Bertoni',  'd2')
40> insert into employee values(6,  'Elke',    'Hansel',   'd2')
41> insert into employee values(7,  'Sybill',  'Moser',    'd1')
42> GO

(1 rows affected)

(1 rows affected)

(1 rows affected)

(1 rows affected)

(1 rows affected)

(1 rows affected)

(1 rows affected)
1> select * from employee
2> GO
emp_no      emp_fname            emp_lname            dept_no
----------- -------------------- -------------------- -------
          1 Matthew              Smith                d3
          2 Ann                  Jones                d3
          3 John                 Barrimore            d1
          4 James                James                d2
          5 Elsa                 Bertoni              d2
          6 Elke                 Hansel               d2
          7 Sybill               Moser                d1

(7 rows affected)
1>
2> CREATE TABLE works_on        (emp_no       INTEGER NOT NULL,
3>                         project_no    CHAR(4) NOT NULL,
4>                         job CHAR (15) NULL,
5>                         enter_date    DATETIME NULL)
6>
7> insert into works_on values (1, 'p1', 'analyst', '1997.10.1')
8> insert into works_on values (1, 'p3', 'manager', '1999.1.1')
9> insert into works_on values (2, 'p2', 'clerk',   '1998.2.15')
10> insert into works_on values (2, 'p2',  NULL,     '1998.6.1')
11> insert into works_on values (3, 'p2',  NULL,     '1997.12.15')
12> insert into works_on values (4, 'p3', 'analyst', '1998.10.15')
13> insert into works_on values (5, 'p1', 'manager', '1998.4.15')
14> insert into works_on values (6, 'p1',  NULL,     '1998.8.1')
15> insert into works_on values (7, 'p2', 'clerk',   '1999.2.1')
16> insert into works_on values (8, 'p3', 'clerk',   '1997.11.15')
17> insert into works_on values (7, 'p1', 'clerk',   '1998.1.4')
18> GO
Msg 2714, Level 16, State 6, Server JAVA2S\SQLEXPRESS, Line 2
There is already an object named 'works_on' in the database.
1>
2> select * from works_on
3> GO
emp_no      project_no job             enter_date
----------- ---------- --------------- -----------------------
          1 p1         analyst         1997-10-01 00:00:00.000
          1 p3         manager         1999-01-01 00:00:00.000
          2 p2         clerk           1998-02-15 00:00:00.000
          2 p2         NULL            1998-06-01 00:00:00.000
          3 p2         NULL            1997-12-15 00:00:00.000
          4 p3         analyst         1998-10-15 00:00:00.000
          5 p1         manager         1998-04-15 00:00:00.000
          6 p1         NULL            1998-08-01 00:00:00.000
          7 p2         clerk           1999-02-01 00:00:00.000
          8 p3         clerk           1997-11-15 00:00:00.000
          7 p1         clerk           1998-01-04 00:00:00.000

(11 rows affected)
1>
2> SELECT emp_fname, emp_lname FROM employee WHERE emp_no = ANY
3>        (SELECT emp_no FROM works_on WHERE project_no = 'p1')
4> GO
emp_fname            emp_lname
-------------------- --------------------
Matthew              Smith
Elsa                 Bertoni
Elke                 Hansel
Sybill               Moser

(4 rows affected)
1>
2> drop table employee
3> GO
1>
2>
           
       








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1.ANY evaluates to true if the result of an inner query contains at least one row that satisfies the comparison