Creating an OpenFileDialog : OpenFileDialog « UI Controls « Silverlight

1. Silverlight
2. UI Controls
3. OpenFileDialog

Creating an OpenFileDialog

    

<UserControl x:Class='SilverlightApplication3.MainPage'
    xmlns='http://schemas.microsoft.com/winfx/2006/xaml/presentation' 
    xmlns:x='http://schemas.microsoft.com/winfx/2006/xaml'
    xmlns:d='http://schemas.microsoft.com/expression/blend/2008' 
    xmlns:mc='http://schemas.openxmlformats.org/markup-compatibility/2006' 
    mc:Ignorable='d' 
    d:DesignWidth='640' d:DesignHeight='480'>
    <Grid x:Name="LayoutRoot" Background="White">
        <Button x:Name="myButton" Content="Launch File Dialog" Height="30" Width="120" Click="myButton_Click" />
    </Grid>
</UserControl>


//File: Page.xaml.cs
using System;
using System.Collections.Generic;
using System.Linq;
using System.Net;
using System.Windows;
using System.Windows.Controls;
using System.Windows.Documents;
using System.Windows.Input;
using System.Windows.Media;
using System.Windows.Media.Animation;
using System.Windows.Shapes;

namespace SilverlightApplication3
{
    public partial class MainPage : UserControl
    {
        public MainPage()
        {
            InitializeComponent();
        }

        private void myButton_Click(object sender, RoutedEventArgs e)
        {
            OpenFileDialog openFileDialog = new OpenFileDialog();
            openFileDialog.Filter = "Text files (*.txt)|*.txt|Xml Files (*.xml)|*.xml";            
            bool? fileWasSelected = openFileDialog.ShowDialog();                      
        }
    }
}

   
    
    
    
  

Related examples in the same category

1.

Retrieving the selection of an OpenFileDialog