Find the cars that are going less than 55 mph, and order by descending PetName : Query « LINQ « VB.Net






Find the cars that are going less than 55 mph, and order by descending PetName

  


Public Class Car
  Public PetName As String = String.Empty
  Public Color As String = String.Empty
  Public Speed As Integer
  Public Make As String = String.Empty

  Public Overloads Overrides Function ToString() As String
    Return String.Format("Make={0}, Color={1}, Speed={2}, PetName={3}", Make, Color, Speed, PetName)
  End Function
End Class

Module Program

  Sub Main()
        Dim myCars As New List(Of Car)(New Car() { _
    New Car With {.PetName = "D", .Color = "Silver", .Speed = 100, .Make = "BMW"}, _
    New Car With {.PetName = "C", .Color = "Tan", .Speed = 90, .Make = "BMW"}, _
    New Car With {.PetName = "B", .Color = "Rust", .Speed = 5, .Make = "Yugo"}, _
    New Car With {.PetName = "A", .Color = "White", .Speed = 43, .Make = "Ford"}})


    Dim subset = From c In myCars _
      Where c.Speed > 55 Order By c.PetName Descending Select c
    Console.WriteLine(vbLf + "Cars going faster than 55, ordered by PetName:")
    For Each c As Car In subset
      Console.WriteLine("Car {0}", c)
    Next

 
  End Sub
End Module

   
    
  








Related examples in the same category

1.Convert Linq result to Array
2.Convert Linq result to List
3.Linq Over Array
4.Linq Over int Array
5.A select statement against object list
6.Filter by name length
7.Create a query expression
8.Convert query to a list of string
9.Get all cars. Similar to Select * in SQL
10.Get differences
11.Get only the pet names
12.Join Person and Salaries lists to get the max and min salary
13.Join two object lists together
14.Reflector Linq result
15.Using where clause to check the first name of a Persion
16.Select by a Property
17.Select by object id
18.Query String Array With Operators