Why is 49, 50, 51, 52 stored in the array when I declare testArray[] = {'1','2','3','4','5'}?
How should i initialize a string array? Thanks
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why can we do this in c?
int n;
scanf("%d",&n);
int a[n];
I thought array is located memory during load time but seems like the above example works during runtime.
Do I misunderstand any thing? can ... |
The ANSI C grammar from -link- give me the following rules for array declarations:
(1) | direct_declarator '[' type_qualifier_list assignment_expression ']'
(2) | direct_declarator '[' type_qualifier_list ']'
(3) | ...
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char *names[] = {
[3] = "foo",
[1] = "bar",
...
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#include<stdio.h>
#include<conio.h>
void insert(int arr[]);
# define LEN 10
int count;
void main(void)
{
clrscr();
int arr[]={20,21,22,23,24};
insert(arr);
getch();
}
void insert(int arr[])
{
if(size==count)
printf("no space");
return;
...
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Between formal parameters in a function definition, like:
void change (int *s)
{
s[0] = 42;
}
And another definition:
void change (int s[])
{
...
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I have a simple function:
DoRead(double *writeArray){
//GblOutData is an array of length 80, where each element is 1
writeArray=GblOutData;
//prints out 1
printf("%f",writeArray[5]);
...
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new struct xyz { struct abc p[0]; //LINE 1 int q; }; > int a[0]; //LINE 2 > Are the declarations in line 1 and line 2 correct? No. An array must have at least one element. Incidentally, you should always indent your code to reflect its structure. -- Keith Thompson ... |
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anson said: #include > int main(void) > { int s[3] = { 1, (3,2), (6, 5, 4)}; > printf ("%d %d %d", s[0], s[1], s[2]); > } ~ ~ >>a.out 1 2 4 > this means the last one within the parenthesis mark will works , what about others ? what happened and why . I want to know ... ... |
Hi, I am having troble declaring a const array. If the array size is small, then one can do as follows: const double array[5] = {1, 2, 3, 4, 5}; What if I have an array of size say 1000 or 10000 which, lets say, I am reading from a data file? Then manually entering the values is impossible. So how ... |
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Thanks Bayint, that works. It's too bad you have to use tricks like memcpy in c instead of something a bit more straightforward. I also didn't know you could include an array layout in a typecast. I'm using it to define the vertices of a cube to draw in OpenGL. I don't think a struct would really work (I might be ... |
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/* I compile with full warnings : gcc -Wall -W -pedantic arr1.c -o arr1 */ #include #define SZ1 256 static const int z = 256; int main(void) { int x = 256; static const int y = 256; char buff1[x]; /* warning: ISO C90 forbids variable-size array buff */ char buff2[y]; /* warning: ISO C90 forbids variable-size array buff */ ... |
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A full declarator is a declarator that is not part of another declarator. The end of a full declarator is a sequence point. If the nested sequence of declarators in a full declarator contains a variable length array type, the type specified by the full declarator is said to be variably modified. |
I'm having a little bit of bother trying to understand the way to declare global variables (infact I'm not sure if this is really the best way to go... so alternative suggestions are also very welcome) My current project is to try to develop a GUI button and am writing it using a combination of C and openGL. I would like ... |
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If I have an constant array of file names that I use - 100+ file names on an SD card. Globally, it works fine to declare the array in one file and use extern in the other files that want to use the array. Is there a way to move the array into my main header file, so that only one ... |
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Hi all, I'm having a problem with a small program that I have. I have a data file containing a column of numbers...I've been able to basically read this column with fscanf and find out how many elements there are, but in my program, I want to declare an array, say float MyArray[Number_of_Elements]; and I put this in the middle of ... |
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depends on what u want to do with the array. static means that there is only 1 instance of it in the entire process. so if your using multi threading there can only be one instances of 'a' across all threads.. but if you want to have a different 'a' in different threads dont use static. if your not using multi ... |
#include #include using namespace std; int main(){ vector < vector < string > > myVect; int i, j; //stick some data in... for (i=0; i<2; i++){ vector < string > innerVect; for (j=0; j<2; j++){ innerVect.push_back("Inner Inner vector"); } innerVect.push_back("Inner vector"); myVect.push_back(innerVect); } printf("read the data out (using iterators)\n\n"); vector < vector < string > >::iterator outterIter = myVect.begin(); ... |
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I'm not an idiot but there are times when my computer sure makes me feel like one. I have several arrays declared in my code yet there are a couple of new ones that I am trying to create that it won't accept as greater than one dimension. good arrays look like: GLfloat eye[3] = { 0.0, 0.0, 10.0 }; GLfloat ... |
no you can't. It just means the number is undefined. You're declaring an array of 3 arrays. The number of elements of each of those 3 arrays is unknown at this time but will have to be fixed at some point. It doesn't even have to be the same number of elements for each I think (not 100% certain here, could ... |
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i havent programmed in C in years, i need to however for a project. anyway, i'm reading in a data file and parsing it using basic file pointers. i read in all the data fine. however, when i try to declare a simple array, say, int my_array[10];, it seg faults. if i remove the code that reads in the data and ... |