How to find the size of an integer array in C.
Any method available without traversing the whole array once, to find out the size of the array..
Thankss..
I'm currently facing with a problem of finding all possible subsets of given integer array which has 200 elements in size. I found a solution using bitmask but it actually only ...
In C, there is no boundary checking or size value built into arrays; arrays are just blocks of memory of a given size. As has already been said, you need to either use a sentinel value to markt he end of the array, or pass the array size with the array, or use another data structure.
#include int foo(const int *array, size_t size, int value) { while ( size-- ) { if ( *array++ == value ) { return 1; } } return 0; } void bar(const int *array, size_t size, int value) { printf("%d is %sfound\n", value, foo(array,size,value) ? "" : "NOT "); } int main(void) { int i, data[] = {1,2,3,5,7}; for (i = ...
I have an integer array of variable size, but generally on the smaller side. The members represent a numerical position. I'm trying to find the most code and CPU efficient way to find matches within the array, to find which members share the same position. I've been using nested for loops to find a single match out of an array of ...
hmm..maybe i didn't explain myself right. I don't care how many bytes are in the array..i just wanna know if there is a way I can find out how many elements an integer array has in it. My first example explains that pretty well. Thanks for your input though i actually learned something new through it. -andy