The customary solution is to pass the function the address of element 0 of the array plus a second argument for the number of elements (not the size of the array). Old C libraries used and array of char as a special case. They passed the address of element 0 cas a char* and the function processed elements until it reached ...
In c++, I need to have arrays of 256 nodes where the number of references in the nodes of an array is not determined until run time. The number of references is passed in to the constructor of a node. How would I get an array of nodes with each node containing 2 references and other array of nodes with 4, ...
Hallo, i have to do a program with gsl library. I have to declare two global array cos i can't pass them to gsl functions. The problem is the size is an input from program. What can i do? I want to try it: ....... /* Declaration global variables */ int elementi ; gsl_vector_complex *s_v= gsl_vector_complex_alloc (elementi) ; double esponenti [elementi] ...
If I have an array which its size is based on the user input, from some material, I need to use malloc function to allocate memory for that array what is known dynamic array. Don't forget to free it. That's fine, however, I like to try things out even I know the program will crash. I have written some test program ...
#define MAX_ROWS 50 #define MAX_COLS 50 /* ... */ int matrix[MAX_ROWS][MAX_COLS] = {0}; int numRows = 0, numCols = 0; /* read the matrix in setting numRows & numCols accordingly with a max of MAX_ROWS and MAX_COLS respectively */ /* use numRows and numCols to print the matrix (instead of MAX_ROWS & MAX_COLS) */
I'm not sure of the board etiquette vis a vis posting responses to questions that may have been answered, but I'll throw something out there for you, woiiford. You don't want to declare the array with the [] notation for what you're talking about. When you declare an array, such as int myArray[10], you're actually declaring a pointer called myArray that ...