I know how to convert binary to decimal. I know at least 2 methods: table and power ;-)
I want to convert binary to decimal and print this decimal. Moreover, I'm not ...
#include <stdio.h>
#include <stdlib.h>
// Print out the binary value of an integer
void binval (int num);
int get_number();
main () {
int num;
num = get_number();
printf("Num = %d\n",num);
...
#include <stdio.h>
#include <math.h>
/* converts to binary */
int main()
{
unsigned int decimalNUM = 0;
printf("Enter a number to be converted to binary.\t");
scanf("%d", ...
hi group, i try to compile code below but my compiler is failing. it tells:- printbin.c: In function main: printbin.c:9: error: invalid operands to binary & i am not able to understand what it mean. how to correct fault? please help i'm only new to C. #include #include main() { int val,npow; printf("enter value:"); scanf("%d",&val); for(npow=31;npow>-1;--npow){ if(val&pow(2,npow))putchar(1); else putchar(0); } } ...
Hello; I am a newbie. A homework assignment was assigned and I am having trouble getting started. The assignment reads: Write a program to print out the binary value of a 16 bit number. Create integers i, count, and mask. Set 'i' to a hex value of 0x1b53. Set mask to a value of 0x8000. Why? print a line to show ...
On Sat, 24 Mar 2007 08:55:36 +0100, Carramba Hi! > >How can I output value of char or int in binary form with printf(); ? > >thanx in advance The C Standards do not define a conversion specifier for printf() to output in binary. The only portable way to do this is to roll your own. Here's a start: printf("%s\n", ...
Hey everyone, It's my first time looking to forums for help. I'm a little new to C programming and I'm in a class that requires us to make a program that takes the input of numbers and prints it in a hex, oct, dec, and bin format. I'm having trouble with the bin format as I'm having it print as a ...
int atob (const char * intMe) { int result = 0; int i; for (i = 0; intMe[i] != '\0'; i++) { result <<= 1; // Shift the values in result left once. Same ase // result *= 2; // if intMe[i] == '0', we don't do anything. if (intMe[i] == '1') { result += 1; } } return result; } ...
I'm writing a program where the user enters an integer and the program should tell them how many ones are in the binary form of the number. In the function I wrote, i need to use recursion. Here is what i have so far: #include int binary( int, int ); int main() { int number2, c; char x='y'; while (x=='y'||x=='Y') ...