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C Data Type Q&A » char » number 

1. How to use std::cout to output a char as a number?    bytes.com

Hi, everyone It might be a simple question, but I really don't know the answer. char c = '1'; cout << c; The above code will only output a '1' rather than 0x31; If I use int cast, it can show the number: cout << (int) c; however, if the c is 0x80, which might be a part of MBCS(multibyte character ...

3. how to transform an aray of char in to a big number    cboard.cprogramming.com

4. How to change a number to char*? Like 50 --> "50"    cboard.cprogramming.com

I have a problem about precision multiplication. The code I wrote below. Code: int charToInt(char x) { return (int)(x-'0'); } char intToChar(int x) { return (char)(x+'0'); } void reverse(char *x, int lenX) { int i; char t; for (i = 0; i < (int)(lenX/2); i++) { t = x[i]; x[i] = x[lenX-i-1]; x[lenX-i-1] = t; } for (i = 0; i ...

5. Do most people store numbers in char?    cboard.cprogramming.com

6. unknown number of chars    cboard.cprogramming.com

Cmon Garfield, I thought you'd got the hang of this Code: #include #include #include #define SEG_LENGTH 21 typedef struct line_segment { char buff[SEG_LENGTH]; struct line_segment *next; } line_seg; line_seg *append_line ( line_seg *head, char *buff ) { // allocate (should check for NULL) line_seg *temp = malloc( sizeof(line_seg) ); // copy data strcpy( temp->buff, buff ); temp->next = ...

7. i want that this program divide the number of char on allchar but it doesnt do?    codeproject.com

Wow, I've actually found that in THE book: the presence of the initializer forces the initialization of the whole array, but if the initializer list doesn't match the array size, missing values are initialized with 0. Funny that over the course of more than 2 decades I never came across that trick before... (and never thought of it myself either :o ...

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