This is probably a question for an x86 FPU expert:
I am trying to write a function which generates a random floating point value in the range [min,max]. The problem is ... |
I'm trying to understand how floating point numbers work.
I think I'd like to test out what I know / need to learn by evaluating the following: I would like to find ... |
The output is
x=1000300 y=1000000, z=1000300
I can understand how I got x and z but c's y's output makes no sense.
#include <stdio.h>
int main()
{ int ...
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ma740988 Consider the equation (flight dynamics stuff): Yaw (Degrees) = Azimuth Angle(Radians) * 180 (Degrees) / 3.1415926535897932384626433832795 (Radians) There's a valid reason to use single precision floating point types. The number of decimal digits guaranteed to be correct on my implementation is 6. (i.e numeric_limits < float >::digits10 = 6 ) If I'm reading the IEEE standard, I'd could paraphrase the ... |
Mukesh_Singh_Nick@yahoo.com said: Why does floating point have a rounding error? Consider 1234.12345678 It's easy enough to deal with 1234. Here are the bits: 10011010010 So let's try to deal with 0.12345678, using binary notation. So 0.1 (binary) is 0.5 (decimal), 0.01 (binary) is 0.25 (decimal), and so on. 0.1 = 1/2 = 0.5 - too large 0.01 = 1/4 = 0.25 ... |
Hi, If in C a variable appears like X=10.000000, I can round it to zero decimal places. ie X=10? I then have to save the number into a variable. The method appears below: **************************************[color=blue] >printf("Round % .f \n", 10.0000000);[/color] and the result will appear on the screen as "10" is there any method to "save" the rounded value as X? Thanks, ... |
itportal wrote:[color=blue] > printf("%.3f ",i); > > rounds the number to 1.235 > > How to round it to 1.234. >[/color] One way is to sprintf() with "%f" specifier to a string buffer, and then truncate resultant string to taste... Cheers Vladimir -- My e-mail address is real, and I read it. |
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i wanted to Round off Float value,but the correct computed value is not returning to calling Function . i have following functions . init -- which calls 'compare' function. compare - which will call rounding function . My issue was when i call "compare" function the return value from "Round_Float" function is not visible in "compare" function . here is code ... |
don't forget that when converting from float ot int, the computer just chops off the decimal places - in effect rounding towards zero. To counter this, add 0.5 if its positive and subtract 0.5 if its negative before going from float to int. To check this try putting in 11.8 and it will go to 11.5 if haven't done it. |
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Rounding a floating point # I have tried to round the float point number to a whole number in 2 different ways: I am trying to round up on the cans of paint. I have tried by using cans = (int)(surface + 0.5)/300; I still get the answer 0 cans even though the initial value of the surface variable is .61. ... |
I have within a program a float variable that is used to store a running total of values of one part of a structure. At the end of the program there is a discrepancy between what the actual figure should be and that stored in the variable. Fragments of code are:- struct record { char type; char name[21]; float value; }; ... |
Can someone tell me how to round float variables? I know there is no preset function to do this, so I either have to make one or use this: http://www.codeproject.com/cpp/floa....asp?print=true I tried adding the files (you can find them via the link) to my project, but it says "StdAfx.h" cannot be found. This file is included in the FloatUtils.h file. If ... |
In my program I am calculating a floating point number and then need to display it in a label. However, the number being displayed is the full floating point number such as 328 .957275390625. Is it possible to round this off to a few decimal places such as 328.96? I know if it was in a stream i could use setprecision ... |
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This example is from this forum. Posted by Salem. CODE #include #include typedef float type; type RoundVal(type num) { printf("Input:%f\n", num); num *= 100; printf("step 1:%f\n", num); num += 0.5; printf("step 2:%f\n", num); num = ... |