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Java Network Q&A » ip » validation 

1. Voting mechanism with IP validation and allowing only one by user: problem in getting user IP address with two app servers and apache in front    stackoverflow.com

We have a voting mechanism that we want to restrict to only allow one vote by user. We've tried to validate by IP address, but the problem is that when we get ...

2. Validating IPv4 string in Java    stackoverflow.com

Bellow method is validating if string is correct IPv4 address it returns true if it is valid. Any improvements in regex and elegance would be very appreciated:

public static boolean validIP(String ...

3. IP address validation with wildcard character    stackoverflow.com

String ip = "1.1.&.&";
String WILDCARD_CHARACTER = "&";
String REGEX_IP_ADDRESS_STRING = "(?:(?:"
        + WILDCARD_CHARACTER
        + "|25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\\.){3}(?:"
    ...

4. Validate IP address    stackoverflow.com

I want to validate IP adress using java code.Validations like it should hve 3 ".",no characters, number in between "." Should be in range.How to da that

5. How to keep validation for IP addresses    coderanch.com

Use Socket.getInetAddress().getAddress() to return the 4 byte IP address. Use it on the Socket object that comes from ServerSocket.accept(), don't be confused by ServerSocket.getInetAdress(), which should return the address of your local server. If you were looking to allow only IP addresses from within a particular sub-net, you could then AND these 4 bytes with the sub-net mask, and see if ...

6. Validate IP address    coderanch.com

You might use a regular expression to check for four clumps of digits separated by dots. See Pattern and Matcher in JDK4 or later. You might use String.split() or StringTokenizer to divide the string into parts and check each part for a valid number You might go further and create an InetAddress object and see if it is reachable. Any of ...

7. how can i validate the ip address    coderanch.com

First of all, 10.02.0.99 and 109.2.8.06 are perfectly valid. Just because they have an extra 0 doesn't mean they aren't valid. 109.2.8.06 is equal to 109.2.8.6. Second, use String.split instead, using "\\." as the regex. The \\ will be resolved to a single \ for the regex, which is used to escape the .

8. IP Address validate - IPv6 + IPv4    forums.oracle.com

Hi, Could you let me know how to validate an IPv6 Address. I could see for IPv4 its straight forward to validate; but for IPv6 there are many different Address modes (from RFC) ... is there any specific code for me to straightaway validate IPv6 address in Java. Please let me know. Thanks In Advance.

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