I am currently calling the following line of code:
java.net.URL connection_url = new java.net.URL("http://:/path");
and when it executes I get the above exception. Any ideas as to why this is happening?
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I mean, how does Java decide which protocols are available? I run some code from inside Eclipse, and it works just fine. Then I run the same code from outside Eclipse, ... |
I read that you could call JavaScript code from a Java Applet by calling
JApplet.getAppletContext().showDocument( "javascript:alert('Hello World');" );
However, when I do this i get the following error:
java.net.MalformedURLException: unknown protocol: javascript
How do I ... |
From a Java program, I need to launch the default browser on a local HTML file, pointed to an anchor inside the file. In Java SE 6, the java.awt.Desktop.browse method ... |
I have a java.net.URL object that uses the HTTPS protocol, e.g.:
https://www.bla.com
And I have to change only the protocol part of this URL object so that when I call it's toString() method ... |
We're trying to use Apache Commons VFS to access something over SFTP. It claims to support SFTP, however we're getting a MalformedURLException when it starts. ... |
I am getting Java exception like:
java.net.MalformedURLException: no protocol
My program is trying to parse an XML string by using:
Document dom;
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
DocumentBuilder db = dbf.newDocumentBuilder();
dom = db.parse(xml);
The XML string contains:
String ...
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URL u=new URL("telnet://route-server.exodus.net");
This line is generating :
java.net.MalformedURLException: unknown protocol: telnet
And i encounter similar problems with other URLs that begin with "news://"
These are URLs extracted from ODP , so i dont understand ... |
I'm copying code from one part of our application (an applet) to inside the app. I'm parsing XML as a String. It's been awhile since I parsed XML, but from the ... |
I' m writing a class to run xjc in java. my code goes as follows:
URL url = new URL("C:\\Users\\Simran\\Desktop\\books.xsd");
SchemaCompiler sc = XJC.createSchemaCompiler();
sc.parseSchema(new InputSource(url.toExternalForm()));
S2JJAXBModel model = sc.bind();
...
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With the following code fragment, if docurl = "about:blank", then I get a java.net.MalformedURLException thrown. I cant believe I am the first person to have to handle such urls so Im ... |
i am using birt-2_6_1 with tomcat 7 along with eclipse IDE to generate reports. i have done the coding for generating chart and save them in tem location as png format. ... |
I tried to register a custom URL handler for a classpath protocol, as described in another thread. Here is the code:
package com.mycompany;
import org.junit.Test;
import java.net.MalformedURLException;
import java.net.URL;
import com.mycompany.protocol.classpath.Handler;
public class ParserTest {
...
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hi tried to run the following code and i am getting the following exception : java.net.MalformedURLException: no protocol: ************************************ public static void main(String[] args) throws Exception { URL url = new URL("\\xxxx10000d\\a.txt"); InputStream is = url.openStream(); BufferedReader br = new BufferedReader(new InputStreamReader(is)); BufferedReader in = new BufferedReader( new InputStreamReader( url.openStream())); String inputLine; while ((inputLine = in.readLine()) != null) System.out.println(inputLine); in.close(); } ... |
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I have used validator which link to digester and error occured like this.. -- -- 13-04-07 08:18:59.840 ERROR - java.lang.IllegalArgumentException: Malformed URL 'classloader:/org/apache/commons/digester/xmlrules/digester-rules.dtd' : unknown protocol: classloader :(ValidatorOperator.java:71)[HttpRequestHandler-5984162] 13-04-07 08:18:59.855 DEBUG - ******************************************* :(ValidatorOperator.java:72)[HttpRequestHandler-5984162] -- this line comes from new ValidatorResources(inputstream in) which I already checked that inputstream is not null -- Please help!! |
Integer ret = (Integer) call.invoke(new Object[] {} ); System.out.println("RECEIVED " + ret + "\n"); }catch (AxisFault fault) { System.err.println("Error : " + fault.toString()); } catch (RemoteException e) { System.out.println("Failed to retrieve user data."); } catch (ServiceException e) { System.out.println("Failed to retrieve user data."); } catch (java.net.MalformedURLException e) { System.out.println("Failed to retrieve user data."); } } } |