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Java Regex Q&A » Development » behavior 

1. Question about a weird Java regex behavior    stackoverflow.com

I'm working on a regex that could match the leading digits and . in a String. But it seems just not working correctly. The regex I'm using is

"^[\\.\\d]+"
Below is my ...

2. Java regex alternation operator "|" behavior seems broken    stackoverflow.com

Trying to write a regex matcher for roman numerals. In sed (which I think is considered 'standard' for regex?), if you have multiple options delimited by the alternation operator, it will ...

3. Java RegEx and linebreaks - bug or expected behavior?    stackoverflow.com

I'm trying to interpret a multiline string with RegEx and just found that matching will fail if the string contains newline characters. I'm NOT using using MULTILINE mode, because I'm not ...

4. Is that a normal Java regex behavior?    stackoverflow.com


I found this in some code I wanted to optimize. Here is the snipet:

tempString = bigBuffer.replaceAll("\\n", "");
tempString = tempString.replaceAll("\\t", "");
Then I decided to use the regex wisely and I did this:
tempString ...

5. different behavior with regex on linux vs windows    coderanch.com

nevermind! On windows I was running within eclipse. In linux I was running bins from a jar. I had renamed an old version of the jar, and didnt realize it would still look in this jar in the lib folder even though it had a different name. And this other jar file also had an xml conf file (by accident). On ...

8. Java RegEx behavior problem    forums.oracle.com

[0] => Array ( [0] => : [1] => :a2 [2] => :a3 [3] => :a4 [4] => :b1 [5] => :ffff [6] => :0000 [7] => :0000 ) So, element ":" is now there, but element "" at the beginning is missing. I tried so long to find an answer about why PHP has another result as Java for the ...

9. Does Java regex support this behavior?    forums.oracle.com

10. RegExp behavior    forums.oracle.com

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