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1. Java Regex - reduce spaces in a string    stackoverflow.com

I dont have time to get my head around regex and I need a quick answer. Platform is Java I need the String "Some text   with spaces" to be converted to ...

2. The Best Way of Trimming Spaces in a String    stackoverflow.com

How do I trim spaces inside leaving only one space taking consideration of performance?

Input:
     AA     BB
Output:
AA BB

Input:
A      A
Output:
A ...

3. Regex in java and ignoring white spaces    stackoverflow.com

I want to write a regex to match on a string and ignore white spaces. For example, a search for 'foobar' would match on 'foo bar'.

4. Java regex help -- white space is killing me    stackoverflow.com

Alright, so I have the following output:

<p style="margin-top: 0">

</p>

string.replaceAll("<p([^>]*)></p>","<br/>");

5. Java regex: newline + white space    stackoverflow.com

should be simple, but I'm going crazy with it. Given a text like:

line number 1
line number 2
 line number 2A
line number 3
 line number 3A
 line number 3B
line number 4

6. Dismissing trailing white space at the end of a String when using a regex?    stackoverflow.com

The problem I’m facing here is that the current regex I created does not fully work. If there is no white space at the end of my String it fails. My ...

7. regular expression for not allowing white space at start    stackoverflow.com

A regular expression to allow only alphabets and numbers and spaces only in between alphabets with a maximum size of 20. ([a-zA-Z0-9]+([\\s][a-zA-Z0-9]+)*){0,20}. This does not allow white space at start, but it ...

8. Regular Expression : Case insensitive match as well as White Space igonre    coderanch.com

9. regex: no-break space woe    forums.oracle.com

10. regex problem with spaces    forums.oracle.com

11. Java Regular Expression for double spaces    forums.oracle.com

I am using ([\\s s]+) this regex for finding double spaces but if in single segment (Text Line) there exists two or more double spaces then it is finding only one from it . Matcher m = Pattern.compile( regexp ).matcher(Segment ); while(m.find) { p.println(" ERROR :: Punctuation (Double Dot ) Error"); } Suggets solution Thanks amit

12. RegEx problem with spaces    forums.oracle.com

Hi, just tried the posted code. The result: [2010-12-23 09:30:00, Hello world] [2010-12-23 09:30:00, Hello world] [2010-12-23x09:30:00, Hello world] [2010-12-23x09:30:00, Hello world] [2010-12-23 09:30:00, Hello world] Seems that the escape works and the blank alone as well, the 'x' is correctly considered and "(?im)" is useless. Can't figure out why my code fails... Anyway thank you Rob