From the Java 6 Pattern documentation:
Special constructs (non-capturing)
(?:X) X, as a non-capturing group
…
(?>X) X, as an independent, ... |
InputString: A soldier may have bruises , wounds , marks , dislocations or other Injuries that hurt him .
ExpectedOutput:
bruises
wounds
marks
dislocations
Injuries
Generalized Pattern Tried:
".[\s]?(\w+?)"+ ... |
I'm trying to match the username with a regex. Please don't suggest a split.
USERNAME=geo
Here's my code:
String input = "USERNAME=geo";
Pattern pat = Pattern.compile("USERNAME=(\\w+)");
...
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I'm new to regex in Java and I can't figure out how to include named capture groups in an expression. I'm writing a ScrewTurn Image Converter for Confluence's Universal ... |
Let's say we have the following input:
<amy>
(bob)
<carol)
(dean>
We also have the following regex:
<(\w+)>|\((\w+)\)
Now we get two matches ( as seen on rubular.com):
<amy> is a match, \1 captures amy, \2 fails(bob) is ... |
I have a very uniform set of data from Radius messages that I need to add into our log management solution. The product offers the ability to use a regex ... |
I've some string like :
(((a * b) + c) * d)
and want to capture parenthesized groups with java regex. I thought this simple regex
Pattern p = Pattern.compile("\\((.*)\\)",Pattern.DOTALL);
would do the work ... |
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My group could either be of the form x/y, x.y or x_y.z. Each group is separated by an underscore. The groups are unordered.
Example:
ABC/DEF_abc.def_PQR/STU_ghi_jkl.mno
I would like to capture the following:
ABC/DEF
abc.def
PQR/STU
ghi_jkl.mno
I have done ... |
In Java, how to get all groups which is inside a group (regular expression).
For example:Using (([A-Z][a-z]+)+)([0-9]+) test a string : "AbcDefGhi12345".
Then get Result:
matches():yes
groupCount():3
group(1):AbcDefGhi
group(2):Ghi
group(3):12345
But I want to get String "Abc", "Def", "Ghi", ... |
I want to strip a SOAP envelope from a message to get at the XML in the body.
I attempted the following;
String strippedOfEnvelopedHeader = msg.replaceAll("(?s)(?i)<(.*):Envelope.*<\1:Body>", "");
I thought that this would stip ... |
Please take a look at the following code:
public static void main(String[] args) {
String s = "a < b > c > d";
String ...
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I want to capture date and some other information from a string in java using regex.
I group my pattern as follows,
"( ( date_variation_1 | date_variation_2) (some_other_info) ) "
And now, I ... |
I have strings like below:
@property.one@some text here@property.two@another optional text here etc
which contains @.+?@ strings inside.
I'd like to capture all these "variables" into groups via one regexp matching but it seems ... |
I am trying to capture the right part after the : using java expr, but in the following code, the printed capture group is the whole string, what's wrong?
String s ...
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An item is a comma delimited list of one or more strings of numbers or characters e.g.
"12"
"abc"
"12,abc,3"
I'm trying to match a bracketed list of zero or more items in Java e.g.
""
"(12)"
"(abc,12)"
"(abc,12),(30,asdf)"
"(qqq,pp),(abc,12),(30,asdf,2),"
which ... |
I have this code: Pattern pat = Pattern.compile("\\Q${\\E.*}");// for ${.*} String input = "123 ${abc} 456 ${xyz} abc "; Matcher matcher = pat.matcher(input); while (matcher.find()) { int start = matcher.start(); int end = matcher.end(); System.out.println("start=" + start + ", end=" + end + ", match string=" + input.substring(start, end)); } I expect it to print 2 lines: start=4, end=8, match string=${abc} ... |
So what you want to make with lower case? Variable of regex ? But first you need to receive result and only after have to make lower case! String s1="JAVA".replaceAll("([A-Z])([A-Z]+)", "$1"); String s2="JAVA".replaceAll("([A-Z])([A-Z]+)", "$2").toLowerCase(); System.out.print(s1); System.out.println(s2); Output: Java replaceAll public String replaceAll(String regex, String replacement) Replaces each substring of this string that matches the given regular expression with the given replacement. ... |
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Hi, I know that in JAVA regular expression "capturing groups are numbered by counting their opening parentheses from left to right", but is there anyway to assign a name to a capturing group, like the way in python: (?P[0-9][0-9][0-9][0-9]) //see regular expression Howto website where this group is named "year" and and be retrieved by the group name. Can I do ... |
Hi all, I have a following-like string "array[10][20][30]" and I need to use a regex to get: "array" "10" "20" "30". Any way how to achieve this? The pattern for "array[10]" is much simplier, but the capturing group witch is matched more times is always replaced by following match, so only the last such match can be obtained. Code snapshot looks ... |
Hi, I 've trouble with capturing group as mention in the example below String s = "KLASSE3"; Pattern p = Pattern.compile("KLASSE( d)"); Matcher m= p.matcher(s); System.out.println( m.groupCount()); System.out.println( m.group(1)); Running this gives : 1 Exception in thread "main" java.lang.IllegalStateException: No match found at java.util.regex.Matcher.group(Matcher.java:421) Tried with 1.5.0_08 and 1.6.0-b105 Thanks for any hint |