| | this is what I did. is there a better way in python?
for k in a_list:
if kvMap.has_key(k):
kvMap[k]=kvMap[k]+1
else:
... | From PDB
(Pdb) help l
l(ist) [first [,last]]
List source code for the current file.
Without arguments, list 11 lines around the current line
or continue the previous listing.
...
| Given a list like this:
num = [1, 2, 3, 4, 5]
There are 10 three-element combinations:
[123, 124, 125, 134, 135, 145, 234, 235, 245, 345]
How can I generate this list?
| I want to rank multiple lists according to their elements how often they appear in each list. Example:
list1 = 1,2,3,4
list2 = 4,5,6,7
list3 = 4,1,8,9
result = 4,1,2,3,4,5,6,7,8 (4 is counted three times, ... | In Python, I've got a list of items like:
mylist = [a, a, a, a, b, b, b, d, d, d, c, c, e]
And I'd like to output something like:
a (4)
b (3)
d ...
| ['a','a','b','c','c','c']
to
[2, 2, 1, 3, 3, 3]
and
{'a': 2, 'c': 3, 'b': 1}
| I have a list of integers and I need to count how many of them are > 0.
I'm currently doing it with a list comprehension that looks like this:
sum([1 for x ...
| | I have a list of numbers I am reading left to right. Anytime I encounter a sign change when reading the sequence I want to count it.
X = [-3,2,7,-4,1,-1,1,6,-1,0,-2,1]
X ...
| Let's say I have a list of objects. (All together now: "I have a list of objects.") In the web application I'm writing, each time a request comes in, I pick ... | I have a list of words and I want to find how many times they occur in a .txt file. The word list is something like as follows:
wordlist = ['cup', ...
| I have nested list :
ip[0] = ['23:30:42.476071', '55729', '192.168.98.138.49341', '201.20.49.239.80', '562034568', -1]
ip[1] = ['23:30:43.110194', '20442', '201.20.49.239.80', '192.168.98.138.49341', '364925831', '562034569']
ip[2] = ['23:30:43.110290', ...
| I am a newbe to Python..
I am trying to find a simple way of getting a count of the number of elements in a list
eg MyList="a", "b", "c"
So I want ... | This is a part of my homework assignment and im close to the final answer but not quite yet. I need to write a function that counts odd numbers in ... | I'm new to python. i've the following code:
liste = 'asdfasfasd:asdfafaergasde' # example, how the string looks like
liste = str.split(':');
if liste.count()>2 :
print "NOT YET SUPPORTED!"
According to the doc | a = [1, 2, 9, 5, 1]
b = [9, 8, 7, 6, 5]
I want to count the number of duplicates between the two lists. So using the above, I want to ... | Im trying to create a number of lists depending on the number in my header_count. The code below should generate 3 lists but i get a syntax error instead.
header_count = 4
for ...
| I want to get the number of times x appears in the nested list.
if the list is:
list = [1,2,1,1,4]
list.count(1)
>>3
This is OK. But if the list is:
list = [[1,2,3],[1,1,1]]
How can I get ... | A have a real problem (and a headache) with an assigment...
I'm in an introductory programming class, and I have to write a function that, given a list, will return the "maximum" ... | I have a list of integers; for example:
l = [1, 2, 3, 4, 4, 4, 1, 1, 1, 2]
I am trying to make a list of the three elements in l ... | (I am brand new to any kind of programming so please be as specific as you can when you answer)
Problem: I have written a program to solve pythonchallenge.com level 2. The ... | Given: a list, such as l=[4,4,4,4,5,5,5,6,7,7,7]
Todo: get the count of an element and keep their occurrence order, e.g.:
[(4,4),(5,3),(6,1),(7,3)]
I could do it with:
tmpL = [(i,l.count(i)) for i in l]
tmpS ...
| I'm asked to create a method that returns the number of occurrences of a given item in a list.. I know how to write a code to find a specific item, ... | Given
listEx = ['cat', 'dog', 'cat', 'turtle', 'apple', 'bird', 'bird']
for i in listEx:
if listEx.count(i) > 1:
print "this item appears more ...
| okay.. so if you read my last thread, youd know, im a noob.. then again.. the project im working on is rather large.. anyways... i know about the ".count()" thingy so for example my list is list = [1, 3, 1, 4, 3] list.count(1) >>2 correct? yes?? if the list is list = [1, 1, 2, 3, 1] can i use ... | | thanks for the reply. I agree with you =) I don't think making a list should be illegal for this assignment. Fortunately, it is relatively easy to do even without list, I have almost completed it without lists -- assuming it's completely possible, I will be done shortly. In the end, kind of lame assignment =) but maybe it will prove ... | def countitems(listtocount, item): itemcounter = 0 for element in listtocount: if type(element) == list: itemcounter = countitems(element, item) else: ... | | Awesome, thanks for the link. This is the code thus far: import fileinput phoneNumbers = list() callTimes = list() dupNumberCount = 0 for line in fileinput.input(['PhoneLog.csv']): phoneNumbers.append(line) userInput2 = int(input('Numbers called more than X times : ')) for line in phoneNumbers: if (int(line.split(',')[1]) >= userInput2): for line2 in phoneNumbers: if (line2.split(',')[1]): phoneNumbers.append(line) dupNumberCount += 1 print('Duplicate phone number count: ' + ... | | Counting-method within lists and classes STILL NEED HELP!! by guldtrassel Thu Feb 26, 2009 7:38 am Hi! I'm just finishing my program which is supposed to count the amount of viewers on each program aired during one specific night. I've divided the information given into two classes, one for Persons (each object containing a list of the program viewed and ... |
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