| | I have the following data structure (a list of lists)
[
['4', '21', '1', '14', '2008-10-24 15:42:58'],
['3', '22', '4', '2somename', '2008-10-24 15:22:03'],
['5', '21', '3', '19', '2008-10-24 15:45:45'],
...
| I'm attempting to code a script that outputs each user and their group on their own line like so:
user1 group1
user2 group1
user3 group2
...
user10 group6
etc. ... | I'm trying to write a little script to clean my directories. In fact I have:
pattern = re.compile(format[i])
...
current_f.append(pattern.search(str(ls)))
and I want to use a list comprehension but when I try:
In [25]: [i for ...
| I have been struggling with managing some data. I have data that I have turned into a list of lists each basic sublist has a structure like the following
<1x>begins
<2x>value-1
<3x>value-2
<4x>value-3
some ...
| Let's say I have a list of arbitrary length, L:
L = list(range(1000))
What is the best way to split that list into groups of n? This is the best structure that ... | This is a question about the relative merits of fast code that uses the standard library but is obscure (at least to me) versus a hand-rolled alternative. In this | Thanks for the answers, I have not used StackOverflow before so I was suprised by the number of answers and the speed of them - its fantastic.
I have not been through ... | | I think list comprehensions may give me this, but I'm not sure: any elegant solutions in Python (2.6) in general for selecting unique objects in a list and providing a count?
(I've ... | I'd like to identify groups of continuous numbers in a list, so that:
myfunc([2, 3, 4, 5, 12, 13, 14, 15, 16, 17, 20])
returns:
[(2,5), (12,17), 20]
And was wondering what the best way ... | Given a list
A = [1 2 3 4 5 6]
Is there any idiomatic (Pythonic) way to iterate over it as though it were
B = [(1, 2) (3, 4) (5, 6)]
other than ... | So I have a list that I want to convert to a list that contains a list for each group of objects.
ie
['objA.attr1', 'objC', 'objA.attr55', 'objB.attr4']
would return
[['objA.attr1', 'objA.attr55'], ['objC'], ... | I have a list that is created within an itertools.groupby operation:
def yield_unpacked_list():
for key, grp in itertools.groupby(something_to_groupby, key=lambda x: x[0]):
subset_of_grp ...
| The opposite of list flattening.
Given a list and a length n return a list of sub lists of length n.
def sublist(lst, n):
sub=[] ; result=[]
...
| I have a list of names, e.g. ['Agrajag', 'Colin', 'Deep Thought', ... , 'Zaphod Beeblebrox', 'Zarquon']. Now I want to partition this list into approximately equally sized sublists, so that the ... | Consider the following simplified case:
lol = [['John','Polak',5,3,7,9],
['John','Polak',7,9,2,3],
['Mark','Eden' ,0,3,3,1],
['Mark','Eden' ,5,1,2,9]]
What would ... | Let's say I have a list like this:
list = [["A",0], ["B",1], ["C",0], ["D",2], ["E",2]]
How can I most elegantly group this to get this list output in Python:
list = [["A", "C"], ["B"], ...
| Give these two lists:
I[2]: list1 = ['r1', 'r1', 'r1', 'r2', 'r2', 'r3']
I[3]: list2 = [1,2,3,1,2,1]
What is the Pythonic way to construct the following dictionary?
I[5]: mydict
O[5]: {'r1': {'n1': 1, 'n2': 2, 'n3': ...
| I am trying to take a list of lists, and return a list of lists which contain each element at an index of the original list of lists. I know that ... | for example :giving a list ['car','bed','stop','pots','arc','tops','z','z','rac','deb']
then with the function: produce
[['arc', 'car', 'rac'], ['bed', 'deb'], ['pots', 'stop', 'tops'], ['z', 'z']]
| My GAE application receives several files in the upload (can be from 0 to N). I have there list in files_arguments list:
files_arguments = self.request.arguments()
I need to take first 5 elements, process ... | I have several CSV files in this format, named n-data.csv where n is the number of threads:
elapsed,label
120,Step 01
260,Step 02
113,Step 03
100,Step 01
200,Step 02
103,Step 03
and I would like to get the average of ... | I have a list like
x = [2, 2, 1, 1, 1, 1, 1, 1]
I would like to put the repeated numbers together like
[[2,2],[1,1,1,1,1,1]]
| I have a list like this [0,0,1,1,1,0,0,0,1,1,0,0,1,1,1,1] and I want to group them and then find the length of each group.So the result will be like that :[[2,0],[3,1].....[4,1]].Any help is appreciated.Thanks.
... | I have a list of lists of strings like so:
List1 = [
['John', 'Doe'],
...
| I have a list that looks like this:
myList = [1, 1, 1, 1, 2, 2, 2, 3, 3, 3]
What I want to do is record the index where the items in ... | input: ['abc', 'cab', 'cafe', 'face', 'goo']
output: [['abc', 'cab'], ['cafe', 'face'], ['goo']]
The problem is simple: it groups by anagrams. The order doesn't matter.
Of course, I can do this by C++ (that's my ... | Hello pythoners, I have a similar problem to one i posted a few weeks ago: I have a list of numbers, ie: [98, 75, 87, 90, 92, 81, 90, 98, 93, 86, 79, 91, 74] I need to append every group of numbers >=90 to separate lists. So my new lists would be: [98], [90, 92], [90, 98, 93], [91] It's ... | Let's say I have a table. Column 1 is a list of people. Column 2 is the type. Column 3 is an arbitary number. Like this: Chris, A, 3 John, B, 3 Betty, A, 1 Steve, C, 6 Paula, B, 11 Tony, A, 4 What I want to do is rewrite the list and group the people by type, and display ... |
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