| | I want to have a function that will return the reverse of a list that it is given -- using recursion. How can I do that?
| num = list(str(1234567))
for n1 in num:
print n1
for n2 in reversed(num):
print '\t', n2
On each iteration, it ... | I want to take a list [0,1,2] and turn it into [0,1,2,2,1,0]. Right now, I've got
r = list(mus)
r.reverse()
mus = mus + r
but it seems like there should be a better way. ... | In Python, what is the best way to create a new list whose items are the same as those of some other list, but in reverse order? (I don't want to ... | i wanted to do something like this but this code return list of None (i think it's because list.reverse() is reversing the list in place):
map(lambda row: row.reverse(), figure)
i tried this one, ... | I was working on writing a small code snippet to reverse a string using list appends and pop.
The script that I wrote is as follows:
someStr = raw_input("Enter some string here:")
strList ...
| The return object is named None for list.reverse(). So this code fails when I call solution(k). Is there any way I can get around making a temporary? Or how should I ... | | What's the best way to iterate over a stack in Python?
a = [1,2,3,4]
while (len(a) > 0)
print a.pop()
# prints 4, 3, 2, 1 in sequence
I couldn't find an isempty method, ... | Why doesn't this work?
# to reverse a part of the string in place
a = [1,2,3,4,5]
a[2:4] = reversed(a[2:4]) # This works!
a[2:4] = [0,0] ...
| I want to create a reverse method for a list. I know there already is such a method built into python but I want to try it from scratch. ... | At the interpreter,
a = [1,2,3,4]
a = a.reverse()
Next when I type a at the interpreter, I get nothing. So it seems a = a.reverse() generates an empty list. Is this by design?
I ... | I have a .py file that takes a list, finds the lowest number, puts it into a new array, removes the lowest number from the first array, and repeats until the ... | in the following example:
foo = ['red', 'white', 'blue', 1, 2, 3]
where: foo[0:6:1] will print all elements in foo. However, foo[6:0:-1] will omit the 1st or 0th element.
>>> foo[6:0:-1]
[3, 2, 1, 'blue', ...
| Here is the file
303620.43,6187793.62
303663.61,6187757.08
303652.22,6187702.51
303580.10,6187685.43
303551.63,6187737.15
303574.88,6187775.11
303610.94,6187773.69
When it is reversed I get
303610.94,6187773.69303574.88,6187775.11
303551.63,6187737.15
303580.10,6187685.43
303652.22,6187702.51
303663.61,6187757.08
303620.43,6187793.62
How do I ensure that the Last line when reversed has a '\n' ?
| What is typically regarded as more Pythonic/better/faster to use, the reverse method or the reversed built-in function?
Both in action:
_list = list(xrange(4))
print _list
rlist = list(reversed(_list))
print rlist
_list.reverse()
print _list
| Expected Result:
>>> createLists(5)
([1, 2, 3, 4, 5], [5, 4, 3, 2, 1], [ -5, -4, -3, -2, -1], [-1, -2, -3, -4, -5])
My code:
# Write a function that returns ...
| How can you produce the following list with range() in Python?
[9, 8, 7, 6, 5, 4, 3, 2, 1, 0]
| | | | Hi, I'm trying to write a program that will finds all the reverse pairs in a word list. There is a semantic error that I cannot find. Can anybody help me? Code: Select all # /usr/bin/python # Filename: reverse_pair.py import bisect def reverse(a): reversed = a[-1:] i = -1 ... | Hello, Suppose, I conider a list L1 = [a0,a1,a2,a3,a4,a5,a6]. I have to get another list L2 which reverses a given part of the list L1 say [a2,a3,a4] but without using any temporary variable to store and also without using any loops. That is L2 = [a0,a1,a4,a3,a2,a5,a6]. In L2 you can see that position of 2,3,4 is reversed as that of L1 ... |
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