| | I have a function that returns an 8 digit long binary string for given parameter:
def rule(x):
rule = bin(x)[2:].zfill(8)
return rule
I want to traverse each index of this string and check if it ... | An example list of lists:
[
["url","name","date","category"]
["hello","world","2010","one category"]
["foo","bar","2010","another category"]
["asdfasdf","adfasdf","2010","one category"]
["qwer","req","2010","another category"]
]
What I wish do to is create a dictionary -> category : [ list of entries ].
The resultant dictionary would be:
{"category" : [["url","name","date","category"]],
"one ...
| let's say I have a list
li = [{'q':'apple','code':'2B'},
{'q':'orange','code':'2A'},
{'q':'plum','code':'2A'}]
What is the most efficient way to return the count of unique ... | I have a list of values and I want to put them in a dictionary that would map each value to it's index.
I can do it this way:
>>> t = ...
| I have a dictionary:
D = { "foo" : "bar", "baz" : "bip" }
and I want to create new dictionary that has a copy of one of it's elements k. So if ... | If dict is not empty, the way I use to access 1st element in dict is:
dict[dict.keys()[0]]
Is there any better way to do this? Thanks.
| My list is like
l1 = [ {k1:v1} , {k2:v2}, {v1:k1} ]
Is there any better way to check if any dictionary in the list is having reverse pair?
| | given:
template = {'a': 'b', 'c': 'd'}
add = ['e', 'f']
k = 'z'
I want to use list comprehension to generate
[{'a': 'b', 'c': 'd', 'z': 'e'},
{'a': 'b', 'c': 'd', 'z': 'f'}]
I know I ... | I need to check if a particular key is present in some dictionary. I can use has_key ?? Is there any other method to compare the items of the list ... | I have a very long list of dictionaries with string indices and integer values. Many of the keys are the same across the dictionaries, though not all. I want to generate ... | In Python,
I have list of dicts:
dict1 = [{'a':2, 'b':3},{'a':3, 'b':4}]
I want one final dict that will contain the sum of all dicts.
I.e the result will be: {'a':5, 'b':7}
N.B: every dict ... | I'm trying to create something following:
dictionary = {
'key1': ['val1','val2'],
'key2': @key1
}
where @key1 is reference to dictionary['key1'].
Thank You in advance.
| I am trying to replace list element value with value looked up in dictionary how do I do that?
list = [1, 3, 2, 10]
d = {'id': 1, 'val': 30},{'id': ... | I have a list of dictionary as follows:
myList=[{'id':1,'key1':'a','key2':'b'},{'id':8,'key1':'c','key2':'d'},
{'id':6,'key1':'a','key2':'p'}]
To find index of element, I am currently executing following statement:
print ...
| How do I count the number of subelements in a nested dictionary in the most efficient manner possible? The len() function doesn't work as I initially expected it to:
>>> food_colors ...
| I just started with Python and have question about Dictionaries in Python. I do searched a lot of to get an awnser for my problem, but nothing helped.
here it is:
I have ... | this is my code :
a={'aa':'aaaa','bb':'bbbbb','cc':'ccccc'....}
print a.pop(['cc'...])
but it show error ,
which is the best simple way to pop many element ,
thanks
| Consider a dict like
dict = {
'Apple': {'American':'16', 'Mexican':10, 'Chinese':5},
'Grapes':{'Arabian':'25','Indian':'20'} }
How do I access for instance a particular element of this dictionary ?
for instance I would like to ... | Not sure if people refer to slightly older questions but
Accessing elements of python dictionary
Consider a dict like
dict = {
'Apple': {'American':'16', 'Mexican':10, 'Chinese':5},
...
| This is homework, so I don't expect the answer, just a point in the right direction.
In python I have a dictionary that is like so:
{'bike101': ('Road Bike',
...
| I have a list
A={'k3': ['b', 3],'k2': ['a', 1],'k1': ['a', 3],'k4': ['c', 2],'k5': ['b', 2]}
I want to sort the above dictionary first by letters 'a','b' and 'c' in an ascending order
and then ... | I have a list with dictionary as elements. Each dictionary has an entry called type. The type field represents a list. What is the simplest/pythonic way of obtaining the list with ... | i have this dictionary
sr = {'DTW':'CNT','FWA':'CNT','GRR':'CNT','IND':'CNT','MKE':'CNT','MLI':'CNT','MSP':'CNT','OMA':'CNT','ORD':'CNT','SBN':'CNT','STL':'CNT','BDL':'EST','BOS':'EST','BWI':'EST','CLE':'EST','CMH':'EST','CVG':'EST','EWR':'EST','IAD':'EST','JFK':'EST','MDT':'EST','PHL':'EST','PIT':'EST','ROC':'EST','ABQ':'CNT','AUS':'CNT','DEN':'CNT','DFW':'CNT','ELP':'CNT','IAH':'CNT','LRD':'CNT','MCI':'CNT','MFE':'CNT','MSY':'CNT','OKC':'CNT','SAT':'CNT','TUL':'CNT','ATL':'EST','BNA':'EST','CLT':'EST','JAX':'EST','MCO':'EST','MEM':'EST','MIA':'EST','RDU':'EST','RIC':'EST','SDF':'EST','SJU':'EST','TPA':'EST','ANC':'WST','HNL':'WST','LAS':'WST','LAX':'WST','PDX':'WST','PHX':'WST','RNO':'WST','SAN':'WST','SEA':'WST','SFO':'WST','SLC':'WST','SMF':'WST','TUS':'WST'}
for s, r in sr.iteritems():
print s, r
but while printing it is printing starting with
JFK EST
MKE CNT
why? why printing is not ... | Is there a way to delete an element from a dictionary in Python?
I know I can just call .pop on the dictionary, but that returns the element that was removed. What ... | I have some headache with this python code.
print "length:", len(pub) # length: 420
pub_dict = dict((p.key, p) for p in pub)
...
| I have a dict that can have three keys url. link and path. These three need to be mutually exclusive when I'm validating the dict i.e. If the key url exists ... | How come that I can easily do a for-loop in Python to loop through all the elements of a dictionary in the order I appended the elements but there's no obvious ... | Before I say a word, let me thank the community for being the authoritative location for my programming queries as of recent. And pretend those compliments weren't expressed using words. Anyway, ... | Given the following code
all_options = { "1": "/test/1", "2": "/test/2", "3": "/test/3" }
selected_options = [ "1", "3" ]
How do I get the entries from all_options where the key matches an entry ... | Here is the solution to the question I had asked here assigning a string with a combination of two and separate them in a list. The earlier question was an ... | I have a list ['a','b','c','d']. I need to construct a dict out of this list with all the elements of the list as keys in the dict with some default value ... | I have main dictionary.
mainDict = {'count': 10, 'a': {'abc': {'additional': 0, 'missing': 0, 'changed': 0}}}
Now i have new dictionary with same keys as in mainDict, called this dictionary as b with ... | | displaying the corresponding elements from the dictionary by cvani Fri Sep 16, 2011 6:23 am Hi, I have written the following code which is about my research in linguistics and trying to print the corresponding elements from the dictionary. Code: Select all import sys param_values = { 'vowels':{ ... | I have a dictionary which has dictionaries and lists inside. I want to use the list elements in order to make some calculations, but the problems is that I don't know how to call or access the elements or values one by one (0, 1, 2 and so forth). For example I can only print the whole list but I would ... | >>> for k in d.keys(): print k for v in d[k]: print ' ',v Key3 Value0 Value1 Value2 Key2 Value0 Value1 Value2 Key1 Value0 Value1 ... | I found several solutions since I left the original posting. The one I like the most involves the use of the lamda function as you have shown. I assume that there is very little performance penalty for using this approach. If you could confirm this I would appreciate it. Thanks for getting back to me as quickly as you did. David ... | Adding elements to a dictionary by j_70 Sun Nov 12, 2006 8:54 am I am processing files to be inserted into a database. The structure looks as follows: DEBIT,10/10/06 1,100,10/11/06 1,100,10/12/06 2,105,10/12/06 DEBIT,10/10/06, 3 The header and footer contain transaction type, transaction date, and the footer has an additional field, number of transactions. The data fields contain sub-transaction type, amount, ... |
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