I am trying to index a numpy.array with varying dimensions during runtime. To retrieve e.g. the first row of a n*m array a, you can simply do
I have a one dimensional NumPy array:
a = numpy.array([2,3,3])
What is the fastest way to iterate through all one dimensional sub-arrays of an n dimensional array in python.
For example consider the 3-D array:
import numpy as np
a = np.arange(24)
a = ...
You have an array of shape (a,b,c) and you want to multiply the second dimension by an array of shape (b)
A for loop would work, but is there a better way?
numpy.array has a handy .tostring() method which produces a compact representation of the array as a bytestring. But how do I restore the original array from the bytestring? numpy.fromstring() only produces ...
I am a python newbie. I was confused on how to access array element dynamically.
I have a list b= [1,2,5,8] that I dynamically obtain so its length can vary. With ...
Would like to build a list of indices into a 2 dimensional bool_ array, where True.
arr = numpy.zeros((6,6), numpy.bool_)
arr[2,3] = True
arr[5,1] = True
results1 = [[(x,y) for (y,cell) in enumerate(arr[x].flat) if ...