Nest if statement in case statement : Switch statement « Statement « C Tutorial






  1. C Tutorial
  2. Statement
  3. Switch statement
#include <stdio.h>
#include <ctype.h>

int main(void)
{
  double number1 = 3.0;
  double number2 = 4.0;
  char operation = '+';
  char reply = 0;      


  switch(operation)
  {
    case '+':                    
      printf("= %lf\n", number1 + number2);
      break;

    case '-':                    
      printf("= %lf\n", number1 - number2);
      break;

    case '*':                    
      printf("= %lf\n", number1 * number2);
      break;

    case '/':
      if(number2 == 0)           
        printf("\n\n\aDivision by zero error!\n");
      else
        printf("= %lf\n", number1 / number2);
       break;

    case '%':                    
      if((long)number2 == 0)
        printf("\n\n\aDivision by zero error!\n");
      else
        printf("= %ld\n", (long)number1 % (long)number2);
      break;

    default:                     
      printf("\n\n\aIllegal operation!\n");
      break;
  }
  return 0;
}

= 7.000000




6.4.Switch statement
6.4.1.The switch statement
6.4.2.In the absence of a break statement, all statements that are followed by matched cases are executed.
6.4.3.break statement stops evaluating any further case statements.
6.4.4.Confused if statement
6.4.5.Use switch to simplify the logic
6.4.6.Two cases, one action
6.4.7.Nest if statement in case statement
6.4.8.Use the switch structure to evaluate a user's response from a menu (without break).
6.4.9.Use switch structure to evaluate characters