Create regex to search for IP address pattern 2 : Regex IP « Regular Expression « C# / CSharp Tutorial






using System;
using System.Text.RegularExpressions;

public class MainClass
{
    static void Main( string[] args ) {

        string pattern = @"([01]?\d\d?|2[0-4]\d|25[0-5])\." +
                         @"([01]?\d\d?|2[0-4]\d|25[0-5])\." +
                         @"([01]?\d\d?|2[0-4]\d|25[0-5])\." +
                         @"([01]?\d\d?|2[0-4]\d|25[0-5])";
        Regex regex = new Regex( pattern );
        Match match = regex.Match( "192.168.1.168" );
        while( match.Success ) {
            Console.WriteLine( "IP Address found at {0} with " +
                               "value of {1}",
                               match.Index,
                               match.Value );

            match = match.NextMatch();
        }
        
    }
}
IP Address found at 0 with value of 192.168.1.168








17.5.Regex IP
17.5.1.Create regex to search for IP address pattern
17.5.2.Create regex to search for IP address pattern 2