Overloading a function with const reference parameters : function overload « Function « C++ Tutorial

1. C++ Tutorial
2. Function
3. function overload

#include <iostream>
using std::cout;
using std::endl;

double larger(double a, double b);
long larger(const long& a, const long& b);

int main() {
  double a_double = 1.5, b_double = 2.5;
  cout << larger(a_double, b_double) << endl;
 
  int a_int = 15, b_int = 25;
  cout << larger(static_cast<long>(a_int), static_cast<long>(b_int))<< endl;
  return 0;
}

double larger(double a, double b) {
  cout << "double larger() called" << endl;
  return a>b ? a : b;
}

long larger(const long& a, const long& b) {
  cout << "long ref larger() called" << endl;
  return a>b ? a : b;
}

double larger() called
2.5
long ref larger() called
25