Using GROUP BY ALL : GROUP BY « Query « SQL Server / T-SQL Tutorial






ALL keyword after GROUP BY uses all row values in the grouping, even if they were not qualified to appear via the WHERE clause.
Null value is eliminated by an aggregate or other SET operation.
7>
8> CREATE TABLE employee(
9>    id          INTEGER NOT NULL PRIMARY KEY,
10>    first_name  VARCHAR(10),
11>    last_name   VARCHAR(10),
12>    salary      DECIMAL(10,2),
13>    start_Date  DATETIME,
14>    region      VARCHAR(10),
15>    city        VARCHAR(20)
16> );
17> GO
1> INSERT INTO employee VALUES (1, 'Jason' ,  'Martin', 5890,'2005-03-22','North','Vancouver');
2> GO

(1 rows affected)
1> INSERT INTO employee VALUES (2, 'Alison',  'Mathews',4789,'2003-07-21','South','Utown');
2> GO

(1 rows affected)
1> INSERT INTO employee VALUES (3, 'James' ,  'Smith',  6678,'2001-12-01','North','Paris');
2> GO

(1 rows affected)
1> INSERT INTO employee VALUES (4, 'Celia' ,  'Rice',   5567,'2006-03-03','South','London');
2> GO

(1 rows affected)
1> INSERT INTO employee VALUES (5, 'Robert',  'Black',  4467,'2004-07-02','East','Newton');
2> GO

(1 rows affected)
1> INSERT INTO employee VALUES (6, 'Linda' ,  'Green' , 6456,'2002-05-19','East','Calgary');
2> GO

(1 rows affected)
1> INSERT INTO employee VALUES (7, 'David' ,  'Larry',  5345,'2008-03-18','West','New York');
2> GO

(1 rows affected)
1> INSERT INTO employee VALUES (8, 'James' ,  'Cat',    4234,'2007-07-17','West','Regina');
2> GO

(1 rows affected)
1> INSERT INTO employee VALUES (9, 'Joan'  ,  'Act',    6123,'2001-04-16','North','Toronto');
2> GO

(1 rows affected)
1>
2> select * from employee;
3> GO
id          first_name last_name  salary       start_Date              region     city
----------- ---------- ---------- ------------ ----------------------- ---------- --------------------
          1 Jason      Martin          5890.00 2005-03-22 00:00:00.000 North      Vancouver
          2 Alison     Mathews         4789.00 2003-07-21 00:00:00.000 South      Utown
          3 James      Smith           6678.00 2001-12-01 00:00:00.000 North      Paris
          4 Celia      Rice            5567.00 2006-03-03 00:00:00.000 South      London
          5 Robert     Black           4467.00 2004-07-02 00:00:00.000 East       Newton
          6 Linda      Green           6456.00 2002-05-19 00:00:00.000 East       Calgary
          7 David      Larry           5345.00 2008-03-18 00:00:00.000 West       New York
          8 James      Cat             4234.00 2007-07-17 00:00:00.000 West       Regina
          9 Joan       Act             6123.00 2001-04-16 00:00:00.000 North      Toronto

(9 rows affected)
1>
2>
3>
4> SELECT start_Date,
5> SUM(salary) Total
6> FROM employee
7> WHERE start_Date BETWEEN '7/1/2001' AND '7/31/2005'
8> GROUP BY ALL Region;
9> GO
Msg 8120, Level 16, State 1, Server BCE67B1242DE45A\SQLEXPRESS, Line 4
Column 'employee.start_Date' is invalid in the select list because it is not contained in either an aggregate function o
r the GROUP BY clause.
1>
2>
3>
4> drop table employee;
5> GO
1>








1.4.GROUP BY
1.4.1.A summary query that counts the number of Billings by Banker
1.4.2.Group by and table join
1.4.3.A summary query with a search condition in the WHERE clause
1.4.4.Extracting partial records using GROUP BY.
1.4.5.GROUP BY with SUM()
1.4.6.both the EmployeeID and CustomerID columns in our GROUP BY
1.4.7.A count for each grouping rather than the full table
1.4.8.Using GROUP BY ALL