Delete with subquery : Subquery « Subquery « SQL Server / T-SQL Tutorial

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SQL Server / T-SQL Tutorial » Subquery » Subquery 
8.1.12.Delete with subquery
4CREATE TABLE employee(
5>    id          INTEGER NOT NULL PRIMARY KEY,
6>    first_name  VARCHAR(10),
7>    last_name   VARCHAR(10),
8>    salary      DECIMAL(10,2),
9>    start_Date  DATETIME,
10>    region      VARCHAR(10),
11>    city        VARCHAR(20)
12);
13> GO
1INSERT INTO employee VALUES (1'Jason' ,  'Martin', 5890,'2005-03-22','North','Vancouver');
2INSERT INTO employee VALUES (2'Alison',  'Mathews',4789,'2003-07-21','South','Utown');
3INSERT INTO employee VALUES (3'James' ,  'Smith',  6678,'2001-12-01','North','Paris');
4INSERT INTO employee VALUES (4'Celia' ,  'Rice',   5567,'2006-03-03','South','London');
5INSERT INTO employee VALUES (5'Robert',  'Black',  4467,'2004-07-02','East','Newton');
6INSERT INTO employee VALUES (6'Linda' ,  'Green' , 6456,'2002-05-19','East','Calgary');
7INSERT INTO employee VALUES (7'David' ,  'Larry',  5345,'2008-03-18','West','New York');
8INSERT INTO employee VALUES (8'James' ,  'Cat',    4234,'2007-07-17','West','Regina');
9INSERT INTO employee VALUES (9'Joan'  ,  'Act',    6123,'2001-04-16','North','Toronto');
10> GO

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1select from employee;
2> GO
id          first_name last_name  salary       start_Date              region     city
----------- ---------- ---------- ------------ ----------------------- ---------- --------------------
          Jason      Martin          5890.00 2005-03-22 00:00:00.000 North      Vancouver
          Alison     Mathews         4789.00 2003-07-21 00:00:00.000 South      Utown
          James      Smith           6678.00 2001-12-01 00:00:00.000 North      Paris
          Celia      Rice            5567.00 2006-03-03 00:00:00.000 South      London
          Robert     Black           4467.00 2004-07-02 00:00:00.000 East       Newton
          Linda      Green           6456.00 2002-05-19 00:00:00.000 East       Calgary
          David      Larry           5345.00 2008-03-18 00:00:00.000 West       New York
          James      Cat             4234.00 2007-07-17 00:00:00.000 West       Regina
          Joan       Act             6123.00 2001-04-16 00:00:00.000 North      Toronto

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1>
2CREATE TABLE title(
3>    id  INTEGER,
4>    job_title VARCHAR(20)
5);
6> GO
1INSERT INTO title VALUES (1'developer');
2INSERT INTO title VALUES (1'manager');
3INSERT INTO title VALUES (2'tester');
4INSERT INTO title VALUES (2'programmer');
5INSERT INTO title VALUES (3'boss');
6INSERT INTO title VALUES (4'sales');
7INSERT INTO title VALUES (5'market');
8INSERT INTO title VALUES (6'coder');
9INSERT INTO title VALUES (7'tester');
10INSERT INTO title VALUES (8'developer');
11INSERT INTO title VALUES (9'manager');
12> GO

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1>
2>
3DELETE FROM Employee
4WHERE ID NOT IN
5>      (SELECT ID FROM Title)
6>
7> drop table employee;
8> drop table title;
9> GO

(rows affected)
1>
2>
8.1.Subquery
8.1.1.Building a Nested Subquery
8.1.2.Using Subqueries to Check for the Existence of Matches
8.1.3.Using Subqueries to Check for the Existence of Matches between two tables
8.1.4.Subqueries are SELECT statements that are nested within another T-SQL statement.
8.1.5.Subqueries and Comparison Operators: =
8.1.6.A subquery can be used with other comparison operators: <
8.1.7.Subqueries and IN Operator
8.1.8.A query that uses three subqueries
8.1.9.Doing calculation with subquery
8.1.10.Subqueries can be nested.
8.1.11.ID NOT IN (SELECT ID FROM Title)
8.1.12.Delete with subquery
8.1.13.Join and sub query
8.1.14.Subquery returned more than 1 value. This is not permitted when the subquery follows =, !=, <, <= , >, >= or when the subquery is used as an expression.
8.1.15.subquery with >=
8.1.16.<> ALL with subquery
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