C# TypeInfo FindInterfaces
Description
TypeInfo FindInterfaces Returns an array of Type objects
representing a filtered list of interfaces implemented or inherited by
the current Type.
Syntax
TypeInfo.FindInterfaces has the following syntax.
public virtual Type[] FindInterfaces(
TypeFilter filter,
Object filterCriteria
)
Parameters
TypeInfo.FindInterfaces has the following parameters.
filter- The delegate that compares the interfaces against filterCriteria.filterCriteria- The search criteria that determines whether an interface should be included in the returned array.
Returns
TypeInfo.FindInterfaces method returns
Example
using System;/*from w ww . ja v a 2 s. com*/
using System.Xml;
using System.Reflection;
public class MyFindInterfacesSample
{
public static void Main()
{
XmlDocument myXMLDoc = new XmlDocument();
Type myType = myXMLDoc.GetType();
TypeFilter myFilter = new TypeFilter(MyInterfaceFilter);
String[] myInterfaceList = new String[] {"System.Collections.ICollection"};
for(int index=0; index < myInterfaceList.Length; index++)
{
Type[] myInterfaces = myType.FindInterfaces(myFilter,
myInterfaceList[index]);
if (myInterfaces.Length > 0)
{
Console.WriteLine("\n{0} implements the interface {1}.",
myType, myInterfaceList[index]);
for(int j =0;j < myInterfaces.Length;j++)
Console.WriteLine("Interfaces supported: {0}.",
myInterfaces[j].ToString());
}
}
}
public static bool MyInterfaceFilter(Type typeObj,Object criteriaObj)
{
if(typeObj.ToString() == criteriaObj.ToString())
return true;
else
return false;
}
}