C# TypeInfo GetConstructor(Type[])

Description

TypeInfo GetConstructor(Type[]) Searches for a public instance constructor whose parameters match the types in the specified array.

Syntax

TypeInfo.GetConstructor(Type[]) has the following syntax.

[ComVisibleAttribute(true)]
public ConstructorInfo GetConstructor(
  Type[] types
)

Parameters

TypeInfo.GetConstructor(Type[]) has the following parameters.

• types - An array of Type objects representing the number, order, and type of the parameters for the desired constructor.
• types - -or-
• types - An empty array of Type objects, to get a constructor that takes no parameters. Such an empty array is provided by the static field Type.EmptyTypes.

Returns

TypeInfo.GetConstructor(Type[]) method returns An object representing the public instance constructor whose parameters match the types in the parameter type array, if found; otherwise, null.

Example

using System;//w ww .  ja v a  2 s.com
using System.Reflection;
using System.Security;

public class MyClass1
{
    public MyClass1(){}
    public MyClass1(int i){}

    public static void Main()
    {
        Type myType = typeof(MyClass1);
        Type[] types = new Type[1];
        types[0] = typeof(int);

        ConstructorInfo constructorInfoObj = myType.GetConstructor(types);
        if (constructorInfoObj != null)
        {
            Console.WriteLine("The constructor of MyClass1 that takes an " + 
                "integer as a parameter is: "); 
            Console.WriteLine(constructorInfoObj.ToString());
        }
    }
}

The code above generates the following result.