C# Convert ToInt16(String, Int32)

Description

Convert ToInt16(String, Int32) converts the string representation of a number in a specified base to an equivalent 16-bit signed integer.

Syntax

Convert.ToInt16(String, Int32) has the following syntax.


public static short ToInt16(
  string value,
  int fromBase
)

Parameters

Convert.ToInt16(String, Int32) has the following parameters.

value - A string that contains the number to convert.
fromBase - The base of the number in value, which must be 2, 8, 10, or 16.

Returns

Convert.ToInt16(String, Int32) method returns A 16-bit signed integer that is equivalent to the number in value, or 0 (zero) if value is null.

Example

The following example attempts to interpret each element in a string array as a hexadecimal string and to convert it to a 16-bit signed integer.


//  w  ww .  j  a v a2 s . c  om
using System;

public class Example
{
   public static void Main()
   {
      string[] hexStrings = { "8000", "0FFF", "f000", "00A30", "D", "-13", 
                              "9AC61", "GAD" };
      foreach (string hexString in hexStrings)
      {
         try {
            short number = Convert.ToInt16(hexString, 16);
            Console.WriteLine("Converted '{0}' to {1:N0}.", hexString, number);
         }
         catch (FormatException) {
            Console.WriteLine("'{0}' is not in the correct format for a hexadecimal number.", 
                              hexString);
         }
         catch (OverflowException) {
            Console.WriteLine("'{0}' is outside the range of an Int16.", hexString);
         }
         catch (ArgumentException) {
            Console.WriteLine("'{0}' is invalid in base 16.", hexString);
         }
      }                                            
   }
}

The code above generates the following result.