C# Decimal Round(Decimal, Int32, MidpointRounding)

Description

Decimal Round(Decimal, Int32, MidpointRounding) rounds a decimal value to a specified precision. A parameter specifies how to round the value if it is midway between two other numbers.

Syntax

Decimal.Round(Decimal, Int32, MidpointRounding) has the following syntax.

public static decimal Round(
  decimal d,//  w  w  w. j  a  v a  2s . co m
  int decimals,
  MidpointRounding mode
)

Parameters

Decimal.Round(Decimal, Int32, MidpointRounding) has the following parameters.

• d - A decimal number to round.
• decimals - The number of significant decimal places (precision) in the return value.
• mode - A value that specifies how to round d if it is midway between two other numbers.

Returns

Decimal.Round(Decimal, Int32, MidpointRounding) method returns The number that is nearest to the d parameter with a precision equal to the decimals parameter. If d is halfway between two numbers, one of which is even and the other odd, the mode parameter determines which of the two numbers is returned. If the precision of d is less than decimals, d is returned unchanged.

Example

The following code shows how to use Decimal.Round(Decimal, Int32, MidpointRounding) method.

using System;/*w ww  .ja v a 2s . co m*/

class DecimalRoundDemo
{
    public static void Main( )
    {
        decimal rounded = decimal.Round( 1.45M, 2, MidpointRounding.AwayFromZero );

        Console.WriteLine( rounded );
    }
}

The code above generates the following result.