C# Double TryParse(String, Double)

Description

Double TryParse(String, Double) converts the string representation of a number to its double-precision floating-point number equivalent. A return value indicates whether the conversion succeeded or failed.

Syntax

Double.TryParse(String, Double) has the following syntax.

public static bool TryParse(
  string s,
  out double result
)

Parameters

Double.TryParse(String, Double) has the following parameters.

• s - A string containing a number to convert.
• result - When this method returns, contains the double-precision floating-point number equivalent of the s parameter, if the conversion succeeded, or zero if the conversion failed. The conversion fails if the s parameter is null or String.Empty, is not a number in a valid format, or represents a number less than MinValue or greater than MaxValue. This parameter is passed uninitialized.

Returns

Double.TryParse(String, Double) method returns true if s was converted successfully; otherwise, false.

Example

The following example uses the TryParse(String, Double) method to convert the string representations of numeric values to Double values. It assumes that en-US is the current culture.

using System;/*ww  w . j  a v a 2s. c  o  m*/

public class Example
{
   public static void Main()
   {
      string[] values = { "1,234.57", "$1,234.57", "-1.643e6", 
                          "-123456789012345662", "123AE6", 
                          null, String.Empty, "ABCDEF" };
      double number;

      foreach (var value in values) {
         if (Double.TryParse(value, out number)) 
            Console.WriteLine("'{0}' --> {1}", value, number);
         else
            Console.WriteLine("Unable to parse '{0}'.", value);      
      }   
   }
}

The code above generates the following result.