C# Math Round(Double)

Description

Math Round(Double) rounds a double-precision floating-point value to the nearest integral value.

Syntax

Math.Round(Double) has the following syntax.

public static double Round(
  double a
)

Parameters

Math.Round(Double) has the following parameters.

• a - A double-precision floating-point number to be rounded.

Returns

Math.Round(Double) method returns The integer nearest a. If the fractional component of a is halfway between two integers, one of which is even and the other odd, then the even number is returned. Note that this method returns a Double instead of an integral type.

Example

In the following example, because the floating-point value .1 has no finite binary representation, the first call to the Round(Double) method with a value of 11.5 returns 11 instead of 12.

using System;/*  w  w w .  j  a  v a  2 s  . c o m*/

public class Example
{
   public static void Main()
   {
      double value = 11.1;
      for (int ctr = 0; ctr <= 5; ctr++)    
         value = RoundValueAndAdd(value);

      Console.WriteLine();

      value = 11.5;
      RoundValueAndAdd(value);
   }

   private static double RoundValueAndAdd(double value)
   {
      Console.WriteLine("{0} --> {1}", value, Math.Round(value));
      return value + .1;
   }
}

The code above generates the following result.