C# Math Truncate(Double)

Description

Math Truncate(Double) calculates the integral part of a specified double-precision floating-point number.

Syntax

Math.Truncate(Double) has the following syntax.

public static double Truncate(
  double d
)

Parameters

Math.Truncate(Double) has the following parameters.

• d - A number to truncate.

Returns

Math.Truncate(Double) method returns The integral part of d; that is, the number that remains after any fractional digits have been discarded, or one of the values listed in the following table. d Return value NaN NaN NegativeInfinity NegativeInfinity PositiveInfinity PositiveInfinity

Example

The following example calls the Truncate(Double) method to truncate both a positive and a negative Double value.

using System;//from  w  w  w.ja  v  a 2s .  co m

public class MainClass{
  public static void Main(String[] argv){  
    double floatNumber;
    
    floatNumber = 32.7865;
    // Displays 32      
    Console.WriteLine(Math.Truncate(floatNumber));
    
    floatNumber = -32.9012;
    // Displays -32       
    Console.WriteLine(Math.Truncate(floatNumber));
  }
}

The code above generates the following result.