C# Random Next()

Description

Random Next() returns a nonnegative random integer.

Syntax

Random.Next() has the following syntax.

public virtual int Next()

Returns

Random.Next() method returns A 32-bit signed integer greater than or equal to zero and less than MaxValue.

Example

The following example generates random integers with various overloads of the Next method.

// w  w  w  . j a  v  a2  s. co  m
using System;

public class RandomNextDemo  
{
    static void Main( )
    {  
        Random randObj = new Random( 1 );

        // Generate six random integers from 0 to int.MaxValue. 
        for( int j = 0; j < 6; j++ )
            Console.WriteLine( randObj.Next( ) );
    }
}

The code above generates the following result.