C# String Join(String, String[], Int32, Int32)

Description

String Join(String, String[], Int32, Int32) concatenates the specified elements of a string array, using the specified separator between each element.

Syntax

String.Join(String, String[], Int32, Int32) has the following syntax.

public static string Join(
  string separator,//w  ww . j  a v a  2  s  .c om
  string[] value,
  int startIndex,
  int count
)

Parameters

String.Join(String, String[], Int32, Int32) has the following parameters.

• separator - The string to use as a separator. separator is included in the returned string only if value has more than one element.
• value - An array that contains the elements to concatenate.
• startIndex - The first element in value to use.
• count - The number of elements of value to use.

Returns

String.Join(String, String[], Int32, Int32) method returns A string that consists of the strings in value delimited by the separator string. -or- String.Empty if count is zero, value has no elements, or separator and all the elements of value are String.Empty.

Example

Sample for String.Join(String, String[], int int)

/*from  www .jav a 2  s .  c  o  m*/
using System;

class Sample {
    public static void Main() {
    String[] val = {"apple", "orange", "grape", "pear"};
    String sep   = ", ";
    String result;

    Console.WriteLine("sep = '{0}'", sep);
    Console.WriteLine("val[] = {{'{0}' '{1}' '{2}' '{3}'}}", val[0], val[1], val[2], val[3]);
    result = String.Join(sep, val, 1, 2);
    Console.WriteLine("String.Join(sep, val, 1, 2) = '{0}'", result);
    }
}

The code above generates the following result.