C# Type GetConstructor(Type[])

Description

Type GetConstructor(Type[]) searches for a public instance constructor whose parameters match the types in the specified array.

Syntax

Type.GetConstructor(Type[]) has the following syntax.

[ComVisibleAttribute(true)]
public ConstructorInfo GetConstructor(
  Type[] types
)

Parameters

Type.GetConstructor(Type[]) has the following parameters.

• types - An array of Type objects representing the number, order, and type of the parameters for the desired constructor.
• types - -or-
• types - An empty array of Type objects, to get a constructor that takes no parameters. Such an empty array is provided by the static field Type.EmptyTypes.

Returns

Type.GetConstructor(Type[]) method returns An object representing the public instance constructor whose parameters match the types in the parameter type array, if found; otherwise, null.

Example

The following example obtains the type of MyClass, gets the ConstructorInfo object, and displays the constructor signature.

using System;//from   w  w  w  .ja va 2 s. c om
using System.Reflection;
using System.Security;

public class MyClass1
{
    public MyClass1(){}
    public MyClass1(int i){}

    public static void Main()
    {
            Type myType = typeof(MyClass1);
            Type[] types = new Type[1];
            types[0] = typeof(int);
            ConstructorInfo constructorInfoObj = myType.GetConstructor(types);
            if (constructorInfoObj != null)
            {
                Console.WriteLine("The constructor of MyClass1 that takes an " + 
                    "integer as a parameter is: "); 
                Console.WriteLine(constructorInfoObj.ToString());
            }
            else
            {
                Console.WriteLine("The constructor of MyClass1 that takes an integer " +
                    "as a parameter is not available."); 
            }
    }
}

The code above generates the following result.