Java Thread How to - Coordinate sender and receiver with CyclicBarrier

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Question

We would like to know how to coordinate sender and receiver with CyclicBarrier.

Answer

import java.util.concurrent.CyclicBarrier;
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
/* w  w w .  ja  v  a 2  s .c  om*/
public class Main {
  public static void main(String[] args) {
    CyclicBarrier barrier = new CyclicBarrier(2);
    Receiver receiver = new Receiver(barrier);
    Sender sender = new Sender(barrier);
    ExecutorService executor = Executors.newFixedThreadPool(2);
    executor.submit(receiver);
    executor.submit(sender);
  }
}
class Receiver implements Runnable {
  CyclicBarrier barrier;
  public Receiver(CyclicBarrier barrier) {
    this.barrier = barrier;
  }
  @Override
  public void run() {
    while (true) {
      try {
        Thread.sleep(2000);
        System.out.println("ACK");
        barrier.await();
      } catch (Exception e) {
        e.printStackTrace();
      }
    }
  }
}
class Sender implements Runnable {
  CyclicBarrier barrier;
  public Sender(CyclicBarrier barrier) {
    this.barrier = barrier;
  }
  @Override
  public void run() {
    while (true) {
      try {
        barrier.await();
        System.out.println("SEND");
      } catch (Exception e) {
        e.printStackTrace();
      }
    }
  }
}

The code above generates the following result.

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