Select a cell: cell (2,1) for JTable in Java
Description
The following code shows how to select a cell: cell (2,1) for JTable.
Example
import java.awt.BorderLayout;
/*from w w w .ja v a2 s.c o m*/
import javax.swing.JFrame;
import javax.swing.JScrollPane;
import javax.swing.JTable;
import javax.swing.ListSelectionModel;
public class Main {
public static void main(String args[]) {
JFrame frame = new JFrame();
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
Object rowData[][] = { { "Row1-Column1", "Row1-Column2", "Row1-Column3" },
{ "Row2-Column1", "Row2-Column2", "Row2-Column3" },
{ "Row3-Column1", "Row3-Column2", "Row3-Column3" }};
Object columnNames[] = { "Column One", "Column Two", "Column Three" };
final JTable table = new JTable(rowData, columnNames);
JScrollPane scrollPane = new JScrollPane(table);
frame.add(scrollPane, BorderLayout.CENTER);
frame.setSize(300, 150);
frame.setVisible(true);
table.setSelectionMode(ListSelectionModel.MULTIPLE_INTERVAL_SELECTION);
table.setColumnSelectionAllowed(true);
table.setRowSelectionAllowed(true);
int row = 2;
int col = 1;
boolean toggle = false;
boolean extend = false;
table.changeSelection(row, col, toggle, extend);
}
}
The code above generates the following result.
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