Handle SAX parser error with DefaultHandler in Java

import java.io.StringReader;
//  ww w.  j  a  va 2s  .co m
import javax.xml.parsers.SAXParser;
import javax.xml.parsers.SAXParserFactory;

import org.xml.sax.Attributes;
import org.xml.sax.InputSource;
import org.xml.sax.SAXException;
import org.xml.sax.SAXParseException;
import org.xml.sax.helpers.DefaultHandler;

public class Main {
  public static void main(String[] argv) throws Exception {
    SAXParserFactory factory = SAXParserFactory.newInstance();
    factory.setValidating(true);
    SAXParser parser = factory.newSAXParser();
    SaxHandler handler = new SaxHandler();
    //parser.parse("xmlFileName.xml", handler);
    
    StringReader sr = new StringReader("<folks><olks>");
    InputSource is = new InputSource(sr);
    parser.parse(is, handler);
    
  }
}

class SaxHandler extends DefaultHandler {
  public void startElement(String uri, String localName, String qName, Attributes attrs)
      throws SAXException {
    if (qName.equals("order")) {
    }
  }
  public void error(SAXParseException ex) throws SAXException {
    System.out.println("ERROR: [at " + ex.getLineNumber() + "] " + ex);
  }
  public void fatalError(SAXParseException ex) throws SAXException {
    System.out.println("FATAL_ERROR: [at " + ex.getLineNumber() + "] " + ex);
  }
  public void warning(SAXParseException ex) throws SAXException {
    System.out.println("WARNING: [at " + ex.getLineNumber() + "] " + ex);
  }
}