We would like to know how to get a node from xml without knowing its level.
import org.xml.sax.Attributes; import org.xml.sax.ContentHandler; import org.xml.sax.SAXException; import org.xml.sax.XMLReader; import org.xml.sax.helpers.DefaultHandler; //from ww w . jav a 2 s.c o m class MyHandler extends DefaultHandler { @Override public void startElement(String uri, String localName, String qName, Attributes attributes) throws SAXException { if (qName.equals("child2")) { // here you go do what you need here with the attributes } } } public class Main { public static void main(String[] args) throws Exception { XMLReader parser = org.xml.sax.helpers.XMLReaderFactory.createXMLReader(); ContentHandler contentHandler = new MyHandler(); parser.setContentHandler(contentHandler); parser.parse("foo.xml"); } }