Java Long.parseLong(String s)

Syntax

Long.parseLong(String s) has the following syntax.

public static long parseLong(String s)   throws NumberFormatException

Example

In the following code shows how to use Long.parseLong(String s) method.


public class Main {
  public static void main(String[] args) {
    System.out.println(Long.parseLong("12345"));
/*from  w  ww . j  a  va2 s  .c  o m*/
  }
}

The output:





















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